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Ymorist [56]
3 years ago
7

Substitute for p and solve for r.

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
P is being divided with r
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(5x – 3y) (3x + 4y)​
MariettaO [177]

Answer:

\boxed{\red{15 {x}^{2}  + 11xy - 12 {y}^{2}}}

Step-by-step explanation:

\blue{(5x - 3y)(3x + 4y)} \\ \blue{5x(3x + 4y) - 3y(3x + 4y)} \\ \blue{15 {x}^{2}  + 20xy - 9xy - 12 {y}^{2} } \\ \pink{=  15 {x}^{2}  + 11xy - 12 {y}^{2} }

6 0
3 years ago
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Step-by-step explanation:

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2 years ago
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yulyashka [42]

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Step By Step Explanation

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7 0
2 years ago
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8th grade math help please zoom in on the question for a better look (will give brainliest and thanks if it's right)
eduard
The two pairs are Pythagorean triples because if you plug the two legs of a right triangle into the Pythagorean theorem(A^2+B^2=C^2), then you will find the measurement for the third side(hypotenuse). i.e. 15^2+12^2=9^2(it's the Pythagorean triple 3,4,5 multiplied by 3). This works with any triple, as long as your using the legs of the triangle and as long as the triangle is a right triangle.
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3 years ago
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