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2 years ago

Please help and thank you! (x4)

Mathematics

1 answer:

postnew [5]2 years ago

8 0

in rectangular form the equation is $x^{2} +y^{2} =3 * x$

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3) Monica is listening to Spotify. She noticed that during one hour, 15 songs were played and 3 of them were country. What is th

Blababa [14]

Answer:

D. 1/5

Step-by-step explanation:

The ratio would be 3/15 and when it's reduced it is 1/5

I hope this helps

8 0

2 years ago

Determine if function. HELLPPP If you awnser correctly i will try and give you a brainlyyyy.

astraxan [27]

Answer: This relation is not a function

Step-by-step explanation:

To find out if a relation is a function, we need to use the vertical line test, which means each input value only has one output value. This graph does not pass that vertical line test.

7 0

2 years ago

Read 2 more answers

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

2 years ago

Simplify the expression:<br><br> 3x (4x-6)<br> —————<br> 2x(3x)

Marina86 [1]

Answer:

$=\frac{2x-3}{x}$

Step-by-step explanation:

$=6x^2\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=\frac{3x\left(4x-6\right)}{2x\cdot \:3x}\\2x\cdot \:3x=6x^2\\=\frac{3x\left(4x-6\right)}{6x^2}\\\mathrm{Cancel\:}\frac{3x\left(4x-6\right)}{6x^2}:\quad \frac{4x-6}{2x}\\=\frac{4x-6}{2x}\\\mathrm{Factor}\:4x-6:\quad 2\left(2x-3\right)\\=\frac{2\left(2x-3\right)}{2x}\\\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1\\=\frac{2x-3}{x}$

7 0

3 years ago

Does addition in the whole numbers have the cancellation property.

Ivanshal [37]

Answer:

Although the cancellation law holds for addition, subtraction, multiplication and division of real and complex numbers (with the single exception of multiplication by zero and division of zero by another number), there are a number of algebraic structures where the cancellation law is not valid.

7 0

2 years ago