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2 years ago

11. The total number of months m that it takes to produce p tennis rackets

Mathematics

1 answer:

Viktor [21]2 years ago

4 0

Your question is missing formula for m which is given as;

formula for $m= \frac{p^3}{90}$

Answer:

a.the inverse of the function is $p=\sqrt[3]{90m}$ .

b.p=12 (thousands)

Step-by-step explanation:

Given Data:

Formula for $m= \frac{p^3}{90}$ , where m is the total number of months it takes to produce p tennis rackets (in thousands).

Required:

a. Find the inverse of the function.

b. How many tennis rackets will be produced in 20 months? Round your answer to the nearest whole tennis racket.

Solution:

a.Inverse of the function:

$m= \frac{p^3}{90}\\\\multiply\ both\ sides\ by\ 90\ we\ get\\p^3=m*90\\\\p^3=90m\\\\taking\ cube\ root\ we\ get\\\\p=\sqrt[3]{90m}$

the inverse of the function is $p=\sqrt[3]{90m}$ ........Eq1

b. How many tennis rackets will be produced in 20 months?

put m=20 in Eq1, we get

$p=\sqrt[3]{90*20}\\\\p=\sqrt[3]{1800}\\\\p=12.16$

If we round the answer to nearest whole tennis racket we get p=12 (thousands)

thus, in 20 moths 12 (thousands) tennis rackets will be produced

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3 years ago

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olganol [36]

Answer:

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2 years ago

Consider a paint-drying situation in which drying time for a test specimen is normally distributed with σ = 7. The hypotheses H0

pshichka [43]

Answer:

(a) The value $\bar x$ = 72.3 is 1.21 standard deviations below the null value of μ.

(b) The mean drying time of paint is not less than 74.

Step-by-step explanation:

The hypothesis for the single mean test is:

H₀: μ = 74 vs. Hₐ: μ < 74.

The information provided is:

σ = 7

n = 25

As the population standard deviation is known, we will use a z-test for single mean.

(a)

The z-score is a Normal distribution with mean 0 and variance 1. It is also defined as the number of standard deviations a raw score is from the mean.

The z-score for sample mean is given by:

$z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}$

If $\bar x$ = 72.3 compute the corresponding z-score as follows:

$z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}$

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(b)

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$p-value=P(Z$

*Use a z-table.

The decision rule says to, reject the null hypothesis if the p-value is less than the significance level α = 0.01 and vice-versa.

p-value = 0.1131 < α = 0.01

The null hypothesis was failed to be rejected.

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marshall27 [118]

Answer:

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