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2 years ago

can someone help me with 18-20 plz!!!

Mathematics

2 answers:

ehidna [41]2 years ago

3 0

Answer:

18 minus 20 is -2

borishaifa [10]2 years ago

3 0

Answer:

-2

Step-by-step explanation:

8-10

impossible

therefore u take 10-8

because we borrowed two from ten=-2

=-2

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Find the slope between these two points: (4,2) and (10,5)

mart [117]

Answer:

Slope is 1/2

Step-by-step explanation:

Slope Formula = m = y2 - y1/x2 - x1

Point = (4,2) and (10,5)

m = y2 - y1/x2 - x1

m = 5 - 2/10 - 4

m = 3/6

m = 1/2

4 0

2 years ago

Please help me solve this problem!

Novay_Z [31]

Answer:

20300m^2

Step-by-step explanation:

first try to imagine the shape bisected into a rectangle and a triangle

to find the missing part of the triangle or the bottom side you need to subtract 70m from 140 m

140m-70m=70m this will be the base of your triangle

now you need the side

230m-60m=170

triangle formula base x height/ 2

70m x 170m=a

11900m=a

now the rectangle

base x height=a

60m x140m=a

8400m=a

finally add the two quantities together

8400m+11900m=a

20300m^2=a

5 0

2 years ago

A book sold 35,300 copies in its first month of release. Suppose this represents 6.3 of the numbers sold to date. How many copie

skelet666 [1.2K]

Answer:

560,317.460

Step-by-step explanation:

The computation of copies that have been sold is shown below:-

we assume the number of copies is x

So, the number of copies in the first month is

= $\frac{6.3}{100} x$

As per the situation the number of sold copies is 35,300 so the equation will be

$\frac{6.3}{100} x = 35,300$

$6.3x = 35,300\times 100$

$x = \frac{35,300\times 100}{6.3}$

after solving the above equation we will get the number of copied that have been sold to date

= 560,317.460

7 0

2 years ago

Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq

AnnyKZ [126]

Answer:

$(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Step-by-step explanation:

Step(i):-

Given that the function

f(x) = $e^{4x} \sqrt{1+e^{2x} }$

Now integrating on both sides, we get

$\int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx$

= $\int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx$

Step(ii):-

Let $1 + e^{2x} = t$

$e^{2x} = t -1$

$2e^{2x}dx = d t$

$e^{2x}dx = \frac{1}{2} d t$

= $\int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx$

= $\int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }$

= $\frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }$

= $\frac{1}{2} \int\limits {(t^{\frac{1}{2} } t^{1} +t^{\frac{1}{2} } ) } \, dx$

$= \frac{1}{2} \int\limits {(t^{\frac{3}{2} } +t^{\frac{1}{2} } ) } \, dx$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C$

= $\frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C$

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Final answer:-

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

3 0

2 years ago

A triangular prism was sliced perpendicular to its bases and through a vertex. What is the shape of the cross section shown in t

natta225 [31]

Answer:

B- A rectangle

Step-by-step explanation:

Got it right on edge

4 0

2 years ago

Read 2 more answers

￼can someone help me with 18-20 plz!!!

can someone help me with 18-20 plz!!!