Question

what is the 18th termin an arithmetic sequence with the first term equal to 6 and the constant difference equal to 17

Answer 1

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ ----------\\ n=18\\ a_1=6\\ d=17 \end{cases} \\\\\\ a_{18}=6+(18-1)(17)\implies a_{18}=6+(17)(17) \\\\\\ a_{18}=6+289 \implies a_{18}=295$