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2 years ago

12

Is there like an agency of Kpop groups in the U.S but for parties and events? People can call and they send you a band for a fee

… I’d really like to know please I’d really appreciate an answer

1 answer:

DaniilM [7]2 years ago

3 0

Answer:

i do belive this a thing but not like a mass corperation

more for artist and there personel.

Step-by-step explanation:

You might be interested in

A square with one side length represented by an expression is shown below

crimeas [40]

It is mentioned in the problem that the shape is a square, hence, we could say that all side's measurement is the same and it is equal. It can be written in a different arrangement of terms, but still, the value to be solved is the same. The sides can be written in the following forms:
S1=6(3X+8)+32+12X
S2=18X+48+32+12X
S3=18X+80+12X
S4=30X+80

3 0

3 years ago

The ratio of boys to girls is 7:12 if there are 76 children how many are girls?

Vikentia [17]

12 girls out of 19, how many out of 76

12 - x
19 - 76

Cross product:

19x= 1152
/19. /19
x= ~61

There are (around) 61 girls

3 0

3 years ago

Read 2 more answers

If the area of the rectangle is 90 km?, then what is the value of the missing side?

r-ruslan [8.4K]

I believe it would be B.
Logically, it’s the only one that makes sense,
As 9x10= 90
None of the others have any way to divide or multiply up to the area,
So yes, B.

5 0

3 years ago

Read 2 more answers

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

Read 2 more answers

Dharmesh has a square garden with a perimeter of 132 feet. Is the area of the garden greater than 1,000 square feet?

Delvig [45]

Answer: Yes. The area is 1089 square feet.

Step-by-step explanation:

For a square, all the sides are equal: L = W

Hence, the perimeter of a square = 4 × L

Perimeter = 4L

132 = 4L

132 ÷ 4 = L

33 = L = W

Area of a square with 33 feet sides = L × L = 33 × 33 = 1089

1089 > 1000

3 0

3 years ago