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lisabon 2012 [21]
3 years ago
15

Diffusion ________.

Chemistry
1 answer:
Scilla [17]3 years ago
3 0

Answer:

a. occurs when particles spread from areas where they are less concentrated to areas where they are more concentrated

Explanation:

Diffusion is the net migration of particles such as molecules

ions, or atom from a region where it is highly concentrated to a lower concentration region. Diffusion is initiated by a concentration gradient. An instance is the existence of a concentration of particles of perfume at one end of a room which eventually spreads across the room.

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The state of matter that is able to be compressed is <br><br> gas <br><br> liquid <br><br> solid
Anarel [89]
Gases are easily compressible

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Explain ocean floor spreading and how this process is related to the mid-ocean ridge
zvonat [6]

Answer:

Seafloor spreading is a process that occurs at mid-ocean ridges, where new oceanic crust is formed through volcanic activity and then gradually moves away from the ridge.

Explanation:

Mid-ocean ridges and seafloor spreading can also influence sea levels. As oceanic crust moves away from the shallow mid-ocean ridges, it cools and sinks as it becomes more dense. ... Seafloor spreading proves that the ocean itself is a site of tectonic activity.

3 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Phoenix [80]

Answer:

Coefficients represents no of moles while subscripts represent no of atoms.

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3 years ago
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A 23.6 g sample of NagPO4 (molar mass 163.94 g/mol) is dissolved in enough water to produce
Gnom [1K]

Taking into account the definition of molarity,  the concentration of Na₃PO₄ in solution is 0.192\frac{moles}{lliter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{lliter}.

<h3>Concentration of Na₃PO₄ in solution</h3>

Being the molar mass of Na₃PO₄ 163.94 g/mole, that is, the amount of mass that a substance contains in one mole, the amount of moles that contains 23.6 g sample of Na₃PO₄ is calculated as:

23.6 gramsx\frac{1 mole}{163.94 grams} = 0.144 moles

Then you know:

  • number of moles= 0.144 moles
  • volume= 750 mL= 0.750 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

Molarity=\frac{0.144 moles}{0.750 L}

Solving:

Molarity= 0.192\frac{moles}{lliter}

Finally, the concentration of Na₃PO₄ in solution is 0.192\frac{moles}{lliter}.

Learn more about

molarity:

brainly.com/question/9324116

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brainly.com/question/7429224

molar mass:

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8 0
2 years ago
Enter your answer in the provided box.The equilibrium constant Kc for the equation2H2(g) + CO(g) ⇌ CH3OH(g)is 35 at a certain te
Sphinxa [80]

Answer:

The concentration of CO is 4.33*10⁻³\frac{moles}{L}

Explanation:

A reversible chemical reaction, as in this case, occurs in both directions: reagents transforming into products (direct reaction) and products transforming back into reagents (reverse reaction).

Chemical Equilibrium is the state in which the direct and indirect reaction have the same reaction rate and is defined by a chemical constant Kc.

Being:

aA + bB ⇔ cC + dD

where A, B, C and D represent the chemical species involved and a, b, c and d their respective stoichiometric coefficients, constant Kc is defined as:

Kc=\frac{[C]^{c}*[D]^{d}  }{[A]^{a} *[B]^{b} }

In the case of the reaction

2 H₂(g) + CO(g) ⇌ CH₃OH(g)

the equilibrium constant Kc is:

Kc=\frac{[CH_{3}OH] }{[H_{2} ]^{2}*[CO] }

You know:

  • Kc=35
  • [CH₃OH] =\frac{4.87*10^{-3}moles }{3.63 L} =1.34*10^{-3} \frac{moles}{L}
  • [H₂]=\frac{3.21*10^{-2}moles }{3.63 L} =8.84*10^{-3} \frac{moles}{L}
  • [CO]=?

Replacing:

35=\frac{1.34*10^{-3} }{(8.84*10^{-3} )^{2} *[CO]}

Solving you get:

[CO]= \frac{1.34*10^{-3} }{(8.84*10^{-3} )^{2} *35}

[CO]=4.33*10⁻³\frac{moles}{L}

<u><em>The concentration of CO is 4.33*10⁻³</em></u>\frac{moles}{L}<u><em /></u>

8 0
4 years ago
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