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kondaur [170]
3 years ago
14

Which of the following is an example of the characteristic of movement?

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
5 0
A. The kitten shivers like she’s cold

those link share ppl are SOOOOOO ANNOYING
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You have 125.0 mL of a solution of H3PO4, bu you don't know its concentration. if you titrate the solution with a 4.56-M solutio
irakobra [83]

Answer:

4.90 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 125.0 mL

M₂ = 4.56 M

V₂ = 134.1 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂  

Substituting the respective values ,  

M₁ *  125.0 mL = 4.56 M *  134.1 mL

M₁ = 4.90 M

6 0
3 years ago
I really need the answers please!
krek1111 [17]

1) D = 13.6 g / mL

2)ethyl alcohol weighs 158g

3)ρ _copper = 8.9 g cm^{3}

Explanation:

1)

D = m / V

=306.0 g / 22.5 mL

D= 13.6 g / mL

2)

density = mass / volume

mass = density × volume  

=0.789g /ml × 200.0 ml

M=158g

Ethyl alcohol weighs 158g

3)

ρ  (density) = Mass  / Volume

ρ _copper = 1896 g / 8.4cm × 5.5cm × 4.6cm

= 1896g / 212.5 cm^{3}

ρ _copper=8.9 g cm^{3}

4 0
3 years ago
what is the volume of the air in a balloon that occupies 0.730 L at 28.0 c if the temperature is lowered to 0.00 C
svetoff [14.1K]

Answer:

The volume of the air is 0.662 L

Explanation:

Charles's Law is a gas law that relates the volume and temperature of a certain amount of gas at constant pressure. This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have. the gas molecules. This is represented by the quotient that exists between volume and temperature will always have the same value:

\frac{V}{T}=k

If you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment and several the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 0.730 L
  • T1= 28 °C= 301 °K (0°C= 273°K)
  • V2= ?
  • T2= 0°C= 273 °K

Replacing:

\frac{0.730 L}{301K}=\frac{V2}{273K}

Solving:

V2=273K*\frac{0.730L}{301K}

V2=0.662 L

<u><em>The volume of the air is 0.662 L</em></u>

6 0
3 years ago
What does a tailor bird do to stich it's nest​
ra1l [238]

Answer:

The tailor bird has a beak like a sewing needle. As thread, it uses silk from cobwebs, cotton from seeds, and fibers of tree bark. This bird selects two or more large green leaves growing close together at the end of a branch and pulls them together.

Explanation:

3 0
3 years ago
Read 2 more answers
a cylinder with a movable piston contains 250 cm3 air at 10°C. if the pressure is kept constant, at what temperature would you e
soldi70 [24.7K]

Answer:

T₂ = 169.89 K

Explanation:

Given data:

Initial volume = 250 cm³

Initial temperature = 10°C (10+273.15 K = 283.15 K)

Final temperature = ?

Final volume = 150 cm³

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 283.15 K × 150 cm³ /  250 cm³

T₂ = 42472.5 K. cm³  / 250 cm³

T₂ = 169.89 K

5 0
3 years ago
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