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kondaur [170]
3 years ago
14

Which of the following is an example of the characteristic of movement?

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
5 0
A. The kitten shivers like she’s cold

those link share ppl are SOOOOOO ANNOYING
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Give the chemical formula and systematic name for aurous sulfide, which is named using the older nomenclature. spelling counts!
Bingel [31]
Aurous is a cation of gold. Gold takes the name "aurum" (Au) with atomic number of 79. In its purest form, the element is bright, slightly yellow, soft, ductile, and malleable. The charge of aurous is +1. Sulfide, on the other hand, has a charge of -2. 

Hence, the chemical formula of the compound is Au₂S and its systematic name is gold (I) sulfide. 
5 0
3 years ago
In general, if a reaction is spontaneous, the reactants possess more free energy than the products.
Inga [223]

In general, if a reaction is spontaneous, the reactants possess more free energy than the products.  

<u>TRUE  </u>

FALSE

6 0
3 years ago
When the following equation is balanced, what is the coefficient for NaNO3?
notka56 [123]

The coefficient for NaNO₃ = 6

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

AI(NO₃)₃ +Na₂SO₄ → Al₂(SO₄) + NaNO₃

give coefficient

aAI(NO₃)₃ +bNa₂SO₄ → Al₂(SO₄)₃ +c NaNO₃

Al, left=a, right=2⇒a=2

N, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6

Na, left=2b, right=c⇒2b=c⇒2b=6⇒b=3

The equation becomes :

2AI(NO₃)₃ +3Na₂SO₄ → Al₂(SO₄)₃ +6NaNO₃

6 0
3 years ago
Use the information from the diagram to calculate the enthalpy of combustion for methane. (HELP ASAPPP!!)
Blizzard [7]

Answer:

where is the diagram sisters

6 0
3 years ago
For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.
vichka [17]

Answer:

\Delta G =-103.95kJ

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

\Delta G =\Delta H-T\Delta S

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ

Best regards!

6 0
3 years ago
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