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zheka24 [161]
3 years ago
8

Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list

. Round your answers to three decimal places where appropriate.)
sin 2θ + sin θ = 0
Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0
Sin(2θ)+sin(<span>θ)=0
use double angle formula: sin(2</span>θ)=2sin(θ)cos(<span>θ).
=>
2sin(</span>θ)cos(θ)+sin(<span>θ)=0
factor out sin(</span><span>θ)
sin(</span>θ)(2cos(<span>θ)+1)=0
by the zero product property,
sin(</span>θ)=0 ...........(a) or
(2cos(<span>θ)+1)=0.....(b)
Solution to (a): </span>θ=k(π<span>)
solution to (b): </span>θ=(2k+1)(π)+/-(π<span>)/3
for k=integer

For [0,2</span>π<span>), this translates to:
{0, 2</span>π/3,π,4π/3}
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