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Naddik [55]
3 years ago
14

What is the surface area of the triangular prism?

Mathematics
2 answers:
pochemuha3 years ago
6 0
The answer to this question would be 5 feet
Anna35 [415]3 years ago
5 0

Answer:

5 feet

Step-by-step explanation:

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Find the are of the shape below
skelet666 [1.2K]

Answer:

Area is 235

Step-by-step explanation:

Split the shape evenly so 11 x 14 and 9 x 9then multly and add

when slpitting up the number some times you have to add or subtract so to get 9 x 9 we just take 20 then take away 11 due to the line going through 20 and 20 - 11 = 9

9 x 9 = 81

11 x 14 = 154

81 + 154 = 235

or

Simular to the first one but the cutting line is different. this time the line cuts through 14

9 x 20 = 180

11 x 5 = 55

180 + 55 = 235

8 0
1 year ago
P is the incenter of △JKL. Find m∠JKP.<br> &amp; can you please explain
dangina [55]

Answer:

  • m∠MKP = 35°

Step-by-step explanation:

<u>Incenter is the intersection of angle bisectors.</u>

  • ∠MJP = ∠OJP, ∠MKP = ∠NKP, ∠NLP = ∠OLP

<u>First find the value of x:</u>

  • 7x - 6 = 5x + 4
  • 7x - 5x = 4 + 6
  • 2x = 10
  • x = 5

<u>Find the angle MJP:</u>

  • 7*5 - 6 = 29°

<u>We know sum of interior angles of a triangle is 180°. Using this find the missing angle measure:</u>

  • 2*m∠MJP + 2*m∠NJP + 2*m∠MKP = 180°
  • m∠MJP + m∠NJP + m∠MKP = 90°
  • 29° + 26° + m∠MKP = 90°
  • m∠MKP = 90° - 55°
  • m∠MKP = 35°
7 0
2 years ago
Please help me I honestly have zero clue how to answer this question
Iteru [2.4K]

Step-by-step explanation:

n = 3 \times 5 {}^{2}   \times  {x}^{3}

Square both sides of the equation.

{n}^{2}  = (3 {}^{2}  \times 5 {}^{4}  \times  {x}^{6} )

5 {n}^{2}  = 5(3 {}^{2}  \times  {5}^{4}  \times  {x}^{6} )

6 0
2 years ago
Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin
julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}

Recall that since both lines are parallel, we have that,

m_1=m_2

Thus

m_2\text{ = 1}

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 ,  y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}

5 0
1 year ago
Please help! I will give brainliest to the correct answer!
vampirchik [111]

Answer:

Use desmos graphing calculator. Thats basically the answer to everything that involves graphing. gimme brainliest >:D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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