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True [87]
3 years ago
8

A key code must contain 6 numerals. There are 10 numerals available. Using these numerals, how many different key codes maybe cr

eated?
A. 340
B. 210
C. 3,480
D. 151,200
Mathematics
1 answer:
shutvik [7]3 years ago
7 0
10/(10-6)=10/4.
(10*9*8*7*6*5*4*3*2*1)/(4*3*2*1)
Numbers that are in the numerator and denominator are cancelled out
10*9*8*7*6*5=151200 codes
* means multiply if you didn't know
The correct answer is D

Hope this helped :)
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3y\geqx-9\qquad|:3\\\\y\geq\dfrac{1}{3}x-3\\\\3x+y > -3\qquad|-3x\\\\y > -3x-3

\left\{\begin{array}{ccc}y\geq\dfrac{1}{3}x-3\\\\y > -3x-3\end{array}\right


y=\dfrac{1}{3}x-3\\\\for\ x=0\to y=\dfrac{1}{3}(0)-3=-3\to(0,\ -3)\\\\for\ x=3\to y=\dfrac{1}{3}(3)-3=1-3=-2\to(3,\ -2)\\\\y=-3x-3\\\\for\ x=0\to y=-3(0)-3=-3\to(0,\ -3)\\\\for\ x=-1\to y=-3(-1)-3=3-3=0\to(-1,\ 0)

y\geq\dfrac{1}{3}x-3

solid line. we shade above the line

y > -3x-3

the dotted line. shadow above the line

Answer in the attachment (the first graph).

5 0
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Read 2 more answers
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