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Grace [21]
3 years ago
8

Suppose a goat was tethered at the middle of a 100-foot-long fence and the length of the rope was 50 feet, as shown in the diagr

am below. Over how much area could the goat graze? (Round your answer to two decimal places.)
What if the point at which the goat was tethered was at the middle of a 50-foot-long fence, as shown in the diagram below? Over how much area could the goat graze? (Round your answer to two decimal places.)
Mathematics
1 answer:
Dvinal [7]3 years ago
8 0
The area the goat can graze is 1/2π(50)²= 1250π sq. feet

The rope length is 50 feet again, thus the results are the same.
 
1/2π(50)²= 1250π sq. feet
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Find the quotient 9 3/5 divided 8/15
Whitepunk [10]
The answer is 81/8
Alternative Forms:
10 1/8 or 10.125
4 0
3 years ago
A) In a group of 60 students, 15 liked maths only, 20 liked science only and 5 did not like
Paladinen [302]

Part (i)

We have 60 students total, and 5 didn't like any of the two subjects, so that must mean 60-5 = 55 students liked at least one subject.

<h3>Answer: 55</h3>

=========================================================

Part (ii)

We have 15 who like math only, 20 who like science only, and 55 who like either (or both). Let x be the number of people who like both classes.

We can then say

15+20+x = 55

x+35 = 55

x = 55-35

x = 20

This means 20 people liked both subjects

<h3>Answer: 20</h3>

=========================================================

Part (iii)

There are 15 people who like math only, and 20 who like both. Therefore, there are 15+20 = 35 people who like math (and some of these people also like science)

<h3>Answer: 35</h3>

=========================================================

Part (iv)

We'll follow the same idea as the previous part. There are 20 people who like science only and 20 who like both subjects. That yields 40 people total who like science (and some of these people also like math).

<h3>Answer: 40</h3>

=========================================================

Part (v)

We'll draw a rectangle to represent the entire group of 60 students. This is considered the universal set. Inside the rectangle will be two overlapping circles to represent math (M) and science (S).

We'll have 15 go in circle M, but outside circle S to represent the 15 people who like math only. Then we have 20 go in circle S but outside circle M to show the 20 people who like science only. We have another copy of 20 go in the overlapped region between the circles. This is the 20 people who like both classes. And finally, we have 5 go outside both circles, but inside the rectangle. These are the 5 people who don't like either subject.

Note how all of the values in the diagram add up to 60

15+20+20+5 = 60

This helps confirm we have the correct values.

<h3>Answer: See the venn diagram below</h3>

3 0
3 years ago
Bc has endpoints b(5 ,9) and c(-4, -3). Find the coordinates of the midpoint of bc
Alex73 [517]
We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.

<span>I hope this helps.</span>
4 0
3 years ago
Read 2 more answers
Statements that are true for a cylinder with radius r and height h.
vampirchik [111]

Answer:

Only the second and third statements are correct:

Doubling <em>r</em> quadruples the volume.

Doubling <em>h</em> doubles the volume.

Step-by-step explanation:

The volume of a cylinder is given by:

\displaystyle V=\pi r^2h

We can go through each statement and examine its validity.

Statement 1)

If the radius is doubled, our new radius is now 2<em>r</em>. Hence, our volume is:

\displaystyle V=\pi (2r)^2h=4\pi r^2h

So, compared to the old volume, the new volume is quadrupled the original volume.

Statement 1 is not correct.

Statement 2)

Using the previous reasonsing, Statement 2 is correct.

Statement 3)

If the height is doubled, our new height is now 2<em>h</em>. Hence, our volume is:

V=\pi r^2(2h)=2\pi r^2h

So, compared to the old volume, the new volume has been doubled.

Statement 3 is correct.

Statement 4)

Statement 4 is not correct using the previous reasonsing.

Statement 5)

Doubling the radius results in 2<em>r</em> and doubling the height results in 2<em>h</em>. Hence, the new volume is:

V=\pi (2r)^2(2h)=\pi (4r^2)(2h)=8\pi r^2h

So, compared to the old volume, the new volume is increased by eight-fold.

Statement 5 is not correct.

7 0
3 years ago
X - 10 &gt; 3
joja [24]

Answer:

x>13

Step-by-step explanation:

4 0
2 years ago
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