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3 years ago

Tony bought a case of notebooks for his classroom priced at $8.50. If sales tax is 6%, what is the total cost after tax?

Mathematics

1 answer:

lara [203]3 years ago

6 0

It should be around 9.095 or just around 9.11 dollars.

Hope this is correct and that it helped!!

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Pls answer ;-;

Svetach [21]

Answer:

The second one (2) is a lie

Step-by-step explanation:

The quantities are all proportional, with 4 donuts costing one dollar being consistant. With this, we can multiply the amount of donuts to 40, and through what we know, we can find that the donuts will cost 10 dollars. This leaves only (2) left.

6 0

2 years ago

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I don’t understand how to solve this

Bezzdna [24]

Answer:

42.1

Step-by-step explanation:

The height of the main triangle is,

h = 47√3/2 (since it's an 30-60-90 triangle)

so to find x,

tan(44) = h/x

x = h/tan(44)

x = 42.1 (rounded to the nearest tenth)

Answered by GAUTHMATH

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3 years ago

7➗1/5 <br> As a fraction plz

marishachu [46]

$\bf 7\div \cfrac{1}{5}\implies \cfrac{7}{1}\div \cfrac{1}{5}\implies \cfrac{7}{1}\cdot \cfrac{5}{1}\implies \cfrac{35}{1}$

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3 years ago

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In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour

Lesechka [4]

Answer:

$54-1.64\frac{21}{\sqrt{16}}=45.39$

$54 +1.64\frac{21}{\sqrt{16}}=62.61$

So on this case the 90% confidence interval would be given by (45.39;62.61)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=54$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=21$ represent the sample standard deviation

n=16 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$