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kozerog [31]
3 years ago
9

Issues with paper based records include a. time spent re-keying data, searching for paper copies, and filing. b. storage volume

and outsourced paper storage costs. c. inability to monitor workflow progress. d. All of the above
Computers and Technology
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer: d) All of the above      

Explanation:

According to the question, paper -based records are the records of information and data that is imprinted or written on paper sheets.This data can creates problem like huge storage space requirement, misplacing of paper record,storage cost, filing time, wasting time re-keying information,etc.

  • All the options are correct because problem like re-keying of data, filing, storing of huge amount of paper data, cost of storage, disruption in following workflow progress etc occur when paper-based data records are kept.
  • Thus, the correct option is option(d).  
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which of the following indicates that the loop should stop when the value in the quantity variable is less than the number 50​
yan [13]

Answer:

while (quantity >= 50)

Explanation:

Required

Stop when quantity is less than 50

To do this, we make use of a while statement and the syntax is:

while (condition){ }

If the loop should stop when quantity is less than 50; then it means the loop would continue when quantity is greater or equal to 50

So, we have:

while (quantity >= 50)

6 0
3 years ago
The concept of "plug and play" is demonstrated by which of the following<br> scenarios?
bagirrra123 [75]

Answer:

Farah has completed a post-secondary education program and is now ready to begin working, without additional training, on her first day .

Explanation:  HoPe ThIs HeLpS

6 0
3 years ago
What is the difference between throughput and bandwidth?
masha68 [24]

Answer: Please find below the answer along with explanation.

Explanation:

For  a given communication channel (for instance, a LAN segment using Ethernet ) the Bandwidth refers to the theoretical maximum data rate that the channel can support, for instance, 100 Mbps in a 100Base T network.

The throughput, instead, refers to the actual data rate achieved in a given communications channel, taking into account the different channel impairments.

For instance, in a LAN segment that uses the original Ethernet 802.3 standard (CSMA/CD), a frequent occurrence of collisions can take down the actual data rate from the theoretical 100 Mbps to a very lower figure, i.e., 5 Mbps.

4 0
3 years ago
The capacity of a communication channel is measured in _______.
PSYCHO15rus [73]
<span>The capacity of a communication channel is measured in gb and gps.</span>
4 0
3 years ago
Read 2 more answers
Simple geometry can compute the height of an object from the the object's shadow length and shadow angle using the formula: tan(
agasfer [191]

Answer:

The program to this question can be given as:

Program:

#include <stdio.h>  //include header files

#include<math.h>

int main()    //main method  

{        

   double treeHeight = 0.0;         //declare variables

and assign value

   double shadowLength = 0.0;  

   double angleElevation =  0.11693706;

   // (0.11693706 radians = 6.7 degrees) convert number into angle.      

   shadowLength = 17.5;  

treeHeight = shadowLength * tan(angleElevation);   //convert number into angle

   printf("Tree height: %lf\n", treeHeight);   //print value.

   return 0;  

}

Output:

Tree height: 2.055778

Explanation:

In the above C language program firstly we include the headers. In this header file, we include a (math.h) header file this file helps to use the math function. Then we declare the main method in the main method we declare the variable that is given in the question that are treeHeight, shadowLength , angleElevation. All the variable datatype is double because it stores the floating-point value. Then we apply the formula that is  treeHeight = shadowLength * tan(angleElevation). In this formula, the treeHeight variable holds the value. Then we print the variable value for print the double value we use the lf(that is long float).

7 0
3 years ago
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