Answer:
N = 187.55
Explanation:
Here you just need to replace the terms and clear the equation.
You already know that,
- First capture: 25 prairie dogs.
- First marked animals: 25 (the whole first capture)
You let these animals leave and then you made another capture.
- Second capture: 135 prairie dogs
- Already Marked animals: 18 (these 18 dogs were caught in the first capture and marked before releasing them)
To know the size of the prairie dogs population you just need to use the following equation and clear N, which is the value that you are looking for.
Number of individual marked in first catch/Total population size, N = Number of individual marked in 2nd catch / Total number of 2nd catch
- Number of individual marked in first catch = 25 dogs
- Total population size, N = this is what we want to know
- Number of individual marked in 2nd catch = 18 dogs
- Total number of 2nd catch = 135 dogs
So now, we need to replace terms
25 / N = 18 / 135
25 / N = 0.1333
N = 25 / 0.1333
N = 187.55
Answer and Explanation:
As I don't have access to live butterflies, the control group would be clay models that do not exhibit warning coloration, e.g. beige / white / brown. In contrast, the experimental group would be the clay models that exhibir a strong warning coloration such as color orange / red.
After preparing the clay 'prey', I would locate them in specific places outside where birds are able to detect them. Moreover, I would use a webcam to monitor the recurrence of birds in the area.
1st experiment: Test whether birds approach the prey that exhibits both warning coloration (experimental group) and dull coloration (control group). Then, record the minutes they spent wandering near the prey.
2nd experiment: Test wheter birds feed on the prey that exhibits both warning coloration (experimental group) and dull coloration (control group). Record time.
Carry out statistical analyses.
Present results and discuss.
Answer should be A if multiple choice
Answer:
I think it's the second one or first one
Answer: false
Explanation: this can only be true if the genes in the genomic library fragments have been identified and if the mutation is an SNP and not an inversion or deletion or insertion, whether they were cloned into plasmids or not.
