Assigning "a" as cost of adult tickets and "c" the cost of children's tickets.
3a + 4c = 107
2a + 3c = 76
elimination method
2(3a + 4c = 107)
-3(2a + 3c = 76)
6a + 8c = 214
-6a - 9c = -228
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0 - c = - 14
c = 14
Then 2a + 3(14) = 76
2a = 76 - 42
2a = 34
a = 34/2
a = 17
The problem here takes a brilliant mind to answer this. This problem can easily be answered using programming because we can not then and there push all the possibilities using paper and pen.
The answer is 3816547290.
Trying all the possibilities starting form 1000000080 (we are sure that the last number should be 0). Then traversing that number until 9999999990. Each traverse, check the number if its divisible to n, so on and so forth.
I'd say the ball player would get 275 hits.
Answer:
$400=75 + 4t
82 tickets must be sold to fund the dance
The answer is: 18 .
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25 - 24/4 -1 = 25 - (24/4) - 1 = 25 - 6 - 1 = 19 - 1 = 18 .
The answer is: 18 .
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