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solmaris [256]
3 years ago
14

Twenty years ago a small town in Texas had a population of 10,000. The population has increased 8% each year since then. What eq

uation would be used to solve this population growth problem? a. P = 20 10,000)^.08 b. P = 10,000(8)^20 c. P = 10,000(20)^1.08 d. P = 10,000(1.08)^20
Mathematics
1 answer:
andrezito [222]3 years ago
4 0

Answer:

yea

Step-by-step explanation:

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Answer:

The simplest form of 108/648 is 16

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-324/18<br> Plz show all the steps of how you got the answer.
kodGreya [7K]

Answer:

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Step-by-step explanation:

Step 1 - divide the numerator and denominator by 18

-324÷18 / 18÷18

Step 2 - divide the numbers

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any expression divided by 1 remains the same

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If ABC and DEF are complementary, then the value of x will be,

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2 years ago
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If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally a group of three cards are drawn f
Step2247 [10]

Answer:  5,499,187,200

<u>Step-by-step explanation:</u>

A coin is tossed 5 times.  

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A six-sided die is rolled 4 times.

There are six options so the possible outcomes are: 6⁴

A group of 3 cards are drawn (without replacement).

The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50

Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:

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3 0
4 years ago
A cone has a height of 2.5 in. and a radius of 5 in. What is the volume of the cone? (Use 3.14 for Pi. Round the answer to two d
Stells [14]

Answer:

V =\frac{1}{3} \pi r^2 h

And replacing we got:

V = \frac{1}{3} (3.14) (5in)^2 (2.5in) = 65.42 in^3

And the best option would be:

65.42 Inches cubed

Step-by-step explanation:

For this case we have the following info given:

h =2.5 in represent the height of the cone

r = 5 in represent the radius

And the volume of the cone is given by;

V =\frac{1}{3} \pi r^2 h

And replacing we got:

V = \frac{1}{3} (3.14) (5in)^2 (2.5in) = 65.42 in^3

And the best option would be:

65.42 Inches cubed

6 0
3 years ago
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