Question

Solve for x. 6x-10≤8 or 1/3 x+6>12

Answer 1

The solution is  

$x\le 3 \:or \:x>18$

$EXPLANATION$

$6x-10\le 8\: or \frac{1}{3}x+6>12$

We group like terms, to obtain;

$6x\le 8+10\: or \frac{1}{3}x>12-6$

Simplify to get,

$6x\le 18\: or \frac{1}{3}x>6$

We further simplify to get;

$x\le 3\: or x>18$

This can also be rewritten as;

$x\le 3, x>18$

Or

$(-\infty 3] \cup (18,+ \infty)$

This can be represented on the number line as shown in the diagram.

Answer 2

Answer: (-∞,3)∪(18,∞)

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You must solve for x, as following:

$6x-10\leq8\\6x\leq18\\x\leq3$

$\frac{1}{3}x+6>12\\x>3(6)\\x>18$

2. Therefore, you have that the result is:

(-∞,3]∪(18,∞)