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belka [17]
4 years ago
6

Solve for x. 6x-10≤8 or 1/3 x+6>12

Mathematics
2 answers:
Feliz [49]4 years ago
6 0

The solution is  

x\le 3 \:or \:x>18

EXPLANATION

6x-10\le 8\: or \frac{1}{3}x+6>12

We group like terms, to obtain;

6x\le 8+10\: or \frac{1}{3}x>12-6

Simplify to get,

6x\le 18\: or \frac{1}{3}x>6

We further simplify to get;

x\le 3\: or x>18

This can also be rewritten as;

x\le 3, x>18

Or

(-\infty 3] \cup (18,+ \infty)

This can be represented on the number line as shown in the diagram.


Nikolay [14]4 years ago
4 0

Answer: (-∞,3)∪(18,∞)


Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You must solve for x, as following:

6x-10\leq8\\6x\leq18\\x\leq3

\frac{1}{3}x+6>12\\x>3(6)\\x>18

2. Therefore, you have that the result is:

(-∞,3]∪(18,∞)


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