Can you take a better pic? and nukber 1 is supplemntary so it is half
3+2+1/2+1/7
5+1/2+1/7
5+7/14+2/14
5+9/14
5 9/14
Answer:
r = 225 Mil/h speed of the airplane in still air
Step-by-step explanation:
Then:
d is traveled distance and r the speed of the airplane in still air
so the first equation is for a 4 hours trip
as d = v*t
d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)
Second equation the trip back in 5 hours
d = 5 * ( r - 25 ) (2)
So we got a system of two equation and two unknown variables d and
r
We solve it by subtitution
from equation (1) d = 4r + 100
plugging in equation 2
4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h
And distance is :
d = 4*r + 100 ⇒ d = 4 * ( 225) + 100
d = 900 + 100
d = 1000 miles
Answer:
c
Step-by-step explanation:
y = 
x + 2 → (1)
2y = 5x + 4 ( divide through by 2 )
y = x + 2 → (2)
the 2 equations are the same and will have infinitely many solutions
