Find the minimum, maximum, range, mean, and median for the data set.

2 answers:

5 0

The correct answer among all the other choices is B. minimum: 37
maximum: 208 range: 171 mean: 100.5 median: 92.5. These are the minimum, maximum, range, mean, and median for the data set 37, 43, 54, 83, 102, 117, 160, 208. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.

Papessa [141]3 years ago

3 0

Minimum: 37
maximum: 208
range: maximum - minimum = 208 - 37 = 171
mean: (37 + 43 + 54 + 83 + 102 + 117 + 160 + 208)/8 = 100.5
median: middle number (83 + 102)/2 = 92.5

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This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

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$y = \frac{48- x^{2} }{4x}$

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$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

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</span>
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