Ask question

Ask question

All categories

wolverine [178]

3 years ago

7

How do you earn $120 from his job yesterday. Today he expects to earn 15% less than yesterday and tomorrow he expects to earn 15

% more than today what is the combined about Haiti expect you earn for the three days

1 answer:

Ilya [14]3 years ago

5 0

They took tax from his work

You might be interested in

point r is at (3, 1.3) and point t is at (3, 2.4) on a coordinate grid. the distance between the two points is

Irina18 [472]

Hello,

d=√((1.3-2.4)²+0²)=1.1

7 0

3 years ago

Karen has 3 1/4 feet of ribbon .She uses 1 3/4 feet to wrap gifts .Which shaded part of the model shows 1 3/4

andriy [413]

Answer:

3 1/4 - 1 3/4 = 1 1/2

4 0

2 years ago

Write an explicit formula for the sequence 3,-9,27,-81

Dominik [7]

The initial value is 3. The common ratio is -9/3 = -3. The general formula is
.. an = a1*r^(n-1)

So, for your values, ...
.. an = 3*(-3)^(n -1)

7 0

3 years ago

Please zoom in before you start solving because there are tricks in here. What is the answer?

blondinia [14]

45 ÷ 3 = 15
21 ÷ 3 = 7
12 ÷ 3 = 4

(4 + 15) x 7 = 133

OR if you’re using bedmas/pedmas

4 + (15 x 7) = 109

7 0

3 years ago

A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored

dem82 [27]

Answer:

Mutually exclusive,

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.

A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

$P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}$

$P(\text{Lemon-lime})=\frac{4}{12}$

$P(\text{Lemon-lime})=\frac{1}{3}$

Let us find probability of finding one orange drink.

$P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}$

$P(\text{Orange})=\frac{4}{12}$

$P(\text{Orange})=\frac{1}{3}$

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

$P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})$

$P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}$

$P(\text{Lemon-lime or orange})=\frac{1+1}{3}$

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Therefore, the probability of choosing a lemon lime or orange is $\frac{2}{3}$ .

8 0

2 years ago