Okay here's an example so if we have 2, 3/2*1/2 we convert the mixed numbers to improper fractions. So in order to solve a mixed number you add the denominator, numerator and whole to get 7/2*1.2
So Multiple
7/2*1/2
Refine the fractions
7/2*2
Multiple the numbers 2*2=4 to get
7/4
and that equals 1, 3/4
Answer:
13 Adults and 6 Kids
Step-by-step explanation:
13*9 = $117
6*5.5 = $33
$117 + $33 = $150
Answer:
D. ![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
Step-by-step explanation:
![\sqrt[3]{9x^3y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9x%5E3y%5E4%7D)
![\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%5Csqrt%5B3%5D%7Bx%5E3%7D%5Csqrt%5B3%5D%7By%5E4%7D)
The
cancels out to become x:
![\sqrt[3]{9}x\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E4%7D)
Split the 
![\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E3%7D%5Csqrt%5B3%5D%7By%5E1%7D)
![\sqrt[3]{y^3} =y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E3%7D%20%3Dy)
![xy\sqrt[3]{9} \sqrt[3]{y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9%7D%20%5Csqrt%5B3%5D%7By%7D)
Put the cube root of y and cube root of 9 together:
![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
Let’s convert all their jumps into inches.
Breanna’s is already in inches (62)
Myquisha jumped 5 feet 4 inches
There are 12 inches in a foot, so
5 feet * 12 inches= 60 inches
Then add the 4 inches
60+4= 64
So Myquisha jumped 64 inches.
Ariana jumped 1 yard, 2 feet, 7 inches
1 yard is equal to 3 feet.
So, she jumped 5 feet 7 inches
12 inches in a foot, so
5*12=60 inches
Add the 7
60+7= 67 inches
So Breanna jumped 62, Myquisha 64 and Ariana 67
In order of shortest to longest:
Breanna, Myquisha, Ariana
Answer:
So, you just end up plugging in your numbers.
y = 28 - 3(1)
y = 28-3
y = 25
Y = 28 - 3(3)
y = 28 - 9
y = 19
y = 28 - 3x
y = 28 - 3(4)
y = 28 - 12
y = 16
y = 28 - 3x
y = 28 - 3(6)
y = 28 - 18
y = 10
Step-by-step explanation: