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Scrat [10]
3 years ago
5

Show that the line with equation 4y+3x=44 is a tangent to the circle with centre (5,1) and radius 5.

Mathematics
1 answer:
viktelen [127]3 years ago
7 0

When a line is a tangent to a circle then the point of a tangent on a circle is perpendicular and also equal to the radius

So for perpendicular.

                                            P = \frac{ax+by+c}{\sqrt{a^2 + b^2} }

4y + 3x - 44 = 0

So, a = 4

      b = 3

      c = -44

      x = 5

      y = 1

Putting the values in the formula, we get

P = -4.2

Since the radius of the circle 5 is not equal  to P, The line is not a tangent to the circle.

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Answer:

x = -2

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Step-by-step explanation:

Given two equations

1. 7x + 10y = 36

2. y = 2x + 9

Substitute 2x + 9 for y in equation 1.

We have

7x + 10y = 36

7x + 10(2x + 9) = 36

Distribute 10 into (2x + 9)

We have

7x + 10 x 2x + 10 x 9 = 36

7x + 20x + 90 = 36

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Subtract 90 from both sides to eliminate 90 on the left side

27x + 90 - 90 = 36 - 90

27x = -54

Divide both sides by 27 to isolate x

27x/27 = -54/27

x = -2

Now substitute -2 into either equation to get y

Using equation 2, we have

y = 2x + 9

= 2 x -2 + 9

= -4 + 9

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y = 5

Check

7(-2) + 10(5) = 36

5 0
3 years ago
Solve the system using elimination.
yan [13]

Answer:

y=-3

Step-by-step explanation:

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-----------------

16y=-48

------------

16       16

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2 years ago
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castortr0y [4]

Answer:

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Step-by-step explanation:

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