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3 years ago

Select the number sentence that illustrates the associative property of addition

Mathematics

2 answers:

vladimir2022 [97]3 years ago

7 0

The answer is b i think i’m not sure but i’m pretty sure it’s b

kow [346]3 years ago

5 0

It’s b I learned it in school

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*WILL GIVE BRAINLIEST FOR BEST ANSWER*

Leto [7]

The answer is Value equals 1583.36 cubic feet

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2 years ago

Kermit The Frog could eat 8 flies in 30 minutes. How long would it take Kermit to eat 20 flies? (write the answer in minutes ¬¬¬

Vedmedyk [2.9K]

Answer:

75 minutes

Step-by-step explanation:

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3 years ago

Mary took a math test and she got four questions incorrect and 21 correct. What percent did answer correctly?

AnnZ [28]

Answer:

84%

Step-by-step explanation:

21 correct + 4 wrong = 25 questions in total

$\frac{21}{25}$ x 4 = $\frac{84}{100}$

$\frac{84}{100}$ = 0.84

0.84 = 84%

6 0

3 years ago

A discount voucher offering 15% off is used to pay a bill. After using the voucher, the bill is reduced to £36.72.

Elena-2011 [213]

We can use the is/of=p/100 method for this problem. Since it's 15% off, this would mean that the bill is 85% of what it was initially. Plug the values into the is/of=p/100 formula.

36.72/x = 85/100

Solve for x.

x=36.72/0.85

x=43.2

So, the bill was $43.20 before applying the voucher discount of 15% off.

3 0

3 years ago

Read 2 more answers

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

3 years ago