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2 years ago

When x=12, y=8. Find x when y=12

1 answer:

6 0

<span>x : y is equal to 12 : 8. These can be reduced or cancelled down to 3 : 2 in the same proportions. Therefore, when y is 12, you have to multiply the smallest value y can be by 6, and must do the same to the smallest x value to retain the proportions. x = 18 when y = 12.</span>

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A region R in the xy-plane is given. Find equations for a transformation T that maps a rectangular region S in the uv-plane onto

ruslelena [56]

X(u, v) = (2(v - c) / (d - c) + 1)cos(pi * (u - a) / (2b - 2a))
y(u, v) = (2(v - c) / (d - c) + 1)sin(pi * (u - a) / (2b - 2a))

As v ranges from c to d, 2(v - c) / (d - c) + 1 will range from 1 to 3, which is the perfect range for the radius. As u ranges from a to b, pi * (u - a) / (2b - 2a) will range from 0 to pi/2, which is the perfect range for the angle. So, this maps the rectangle to R.

6 0

2 years ago

PLEASE HELPPPPP ME PLEASE I DONT KNOW WHAT TO DO ☹️#7

nirvana33 [79]

Given:

The function is:

$f(x)=-2x+5$

To find:

The inverse of the given function, then draw the graphs of function and its inverse.

Solution:

We have,

$f(x)=-2x+5$

Step 1: Substitute $f(x)=y$ .

$y=-2x+5$

Step 2: Interchange x and y.

$x=-2y+5$

Step 3: Isolate variable y.

$2y=5-x$

$y=\dfrac{5-x}{2}$

Step 4: Substitute $y=g(x)$ .

$g(x)=\dfrac{5-x}{2}$

Hence, the inverse of the given function is $g(x)=\dfrac{5-x}{2}$ and the graphs of these functions are shown below.

8 0

2 years ago

How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your

Rasek [7]

Polygon Diagonals. The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).

3 0

2 years ago

The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?

gladu [14]

We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub

p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
$p= \frac {(x-6)(x+1)(x+4)}{(x-2)}$

7 0

3 years ago

ecn 221 The sodium content of a popular sports drink is listed as 206 mg in a 32-oz bottle. Analysis of 14 bottles indicates a s

spayn [35]

Answer:

$H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}$

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 206 mg

Sample mean, $\bar{x}$ = 217.5 mg

Sample size, n = 14

Sample standard deviation, s = 14.9 mg

Claim:

The mean sodium content for the sports drink is not 206 mg. It is different than 206 mg.

Thus, we design the null and the alternate hypothesis

$H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}$

We use two-tailed t test to perform this hypothesis.

3 0

2 years ago