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Vesna [10]
3 years ago
11

I put the wrong picture on the last one but this is still due soon

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Answer:

The point ”A“ is the point that corresponds to the last entry in the table.

Step-by-step explanation:

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tamaranim1 [39]

Answer:

  • The function is injective but nor surjective

Step-by-step explanation:

<u>We see that:</u>

  • f(x) = x³

<u>For any x₁ and x₂ ∈ N, </u>

  • f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers

It it confirmed one-to-one, hence it is injective

<u>Check the surjectivity:</u>

f(x) = y ∈ N

  • x³ = y
  • y = ∛x

<u>Let y = 2, then:</u>

  • 2 = x³
  • x = ∛2 ∉ N

Since x is not natural, the function is not surjective

6 0
2 years ago
Read 2 more answers
What is the purpose of a standard drink measurement? It allows you to determine if you're getting what you paid for It is a cons
Law Incorporation [45]

Answer:

It is a consistent way of measuring the amount of alcohol in a drink.

Step-by-step explanation:

A standard drink measure is principally used to measure the amount of alcohol in a drink. It may be referred to as equalling the amount you of an alcoholic drink. The standard drink measure contains approximately 14 grams of alcohol. Hence, with with the standard drink measure, a consumer obtain a consistent measure of the alcohol content he/she is consuming. The standard drink measure is an alcohol related measure and not just any drink or food guage.

6 0
3 years ago
Simplify the following expression 5(m+1)-1
nevsk [136]

5(m + 1) - 1 \\ 5m + 5 - 1 \\ 5m + 4

4 0
2 years ago
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The owner of an electronics store received a shipment of MP3 players at a cost of $64.25 each. If he sells the MP3 players for $
Marizza181 [45]
Your answer to your question should be B if not then i dont know 
7 0
3 years ago
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1) Suppose f(x) = x2 and g(x) = |x|. Then the composites (fog)(x) = |x|2 = x2 and (gof)(x) = |x2| = x2 are both differentiable a
Rufina [12.5K]

Answer:

This contradict of the chain rule.

Step-by-step explanation:

The given functions are

f(x)=x^2

g(x)=|x|

It is given that,

(f\circ g)(x)=|x|^2=x^2

(g\circ f)(x)=|x^2|=x^2

According to chin rule,

(f\circ g)(c)=f(g(c))=f'(g(c)g'(c)

It means, (f\circ g)(c) is differentiable if f(g(c)) and g(c) is differentiable at x=c.

Here g(x) is not differentiable at x=0 but both compositions are differentiable, which is a contradiction of the chain rule

3 0
3 years ago
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