Answer:
0.25%
Explanation:
20 people start the new population. So there are 20 genes or 40 alleles for the recessive disorder phenylketonuria. 2 out of 40 alleles are recessive for the condition hence frequency of the allele = 2/40 = 0.05
Frequency of the allele does not change when the population increases so it is in Hardy-Weinberg equilibrium. According to it, if q is the frequency of recessive allele, q² = frequency of the recessive condition
Here, q = 0.05 So,
q² = (0.05)² = 0.0025
In percentage, it is 100 * 0.0025 = 0.25%
Hence, incidence of phenylketonuria in the new population is 0.25%
Answer:
The correct answer is - option C.
Explanation:
The case in this the biological exterminators asks to use the biological concept which includes spraying the solution of the juvenile hormone to get rid of nymphs of specific insect and according to the assumption, this solution causes some alteration on the ability to reproduce of such nymphs and leads to only nonreproductive ones.
On the given condition the increasing of nymphs, the number of adult nymphs or decreasing of nymphs can not be condition and as the reproductive ability is affected the number of nymphs would be the same.
Thus, the correct answer would be - option C.
I'm gonna say D HOPE IT HELPSSSSSS
While living organisms contain a number of different elements, some elements are found in greater abundance in living organisms. These elements are oxygen, carbon, hydrogen, nitrogen, calcium and phosphorus.
