All categories

3 years ago

What is the role of DNA in transmitting genetic information?

1 answer:

6 0

It contains the bases that form the code to produce specific proteins that the organism needs to help determine its traits. So because of that, DNA stores, copies and transmits the genetic information in a cell.

You might be interested in

Which of the following goes in box 3

Alexeev081 [22]

Glucose is the Answe Yo

4 0

3 years ago

HELP ME QUICKLY FAST!!!!!! How does the heat move through the space between the Sun and the Earth? Match the heat transfer mecha

zheka24 [161]

It is because of what we called Greenhouse Gases. Greenhouse Gases absorbs the heat of the sun and brings it out to the earth. The heat of the sun travels 8 minutes and 20 seconds.

4 0

4 years ago

A normal plant cell holds water in the vacuole of the cell. This large organelle also gives the cell support. Suppose a plant is

BigorU [14]

<span>The water diffuses out of the cell to equalize the solute concentrations

Salt is too big to pass through the cell and water is the only so water tries to "balance" the concentration on the inside and outside.
</span>

4 0

3 years ago

Read 2 more answers

Two different enzymes catalyze the same reaction and both exhibit the same Vmax. When Enzyme A was run with a 40 uM substrate, t

Vinil7 [7]

Answer:

a) k_m = 4.08 uM

V_{max} = 20.07 uM/min

b) k_m = 8.16 uM

Explanation:

Given that:

For Enzyme A:

the substrate concentration [S] = 40 uM

the initial velocity rate v = 10 uM/min

when it was 4mM, v = 20 uM/min

i.e.

at 4mM = 4000 uM;

Using Michealis -menten equation;

when v = 10

$V = \dfrac{V_{max}[S]}{k_m+[S]}$

∴

$10 = \dfrac{V_{max}\times 40}{k_m + 40}$

$10 (k_m + 40) = V_{max}40$

$40V_{max} -10k_m = 400 --- (1)$

when v= 20

$20= \dfrac{V_{max}\times 4000}{k_m + 4000}$

$20 (k_m + 4000) = V_{max}4000$

$4000V_{max} -20k_m = 8000 --- (2)$

equating equation (1) and (2):

$40V_{max} -10k_m = 400 --- (1)$

$4000V_{max} -20k_m = 8000 --- (2)$

let multiply equation (1) by 100 and equation (2) by 1

4000V_{max} - 1000K_m = 4000

0 -980k_m = 4000

k_m = 4000/-980

k_m = 4.08 uM

replacing the value of k_m into equation (1)

40{V_max } - 10(4.08) = 400

40{V_max } - 40.8 = 400

40{V_max } = 400 + 40.8

40{V_max } = 440.8

V_{max} = 440.8/40

V_{max} = 11.02 uM/min

Since V_{max} of A ie equivalent to that of B; then:

V_{max} of B = 11.02 uM/min

Here;

[S] = 80 uM

V = 10 uM/min

∴

$10 = \dfrac{11.02 \times 80}{k_m + 80 }$

10(k_m +80) = 881.6

10k_m = 881.6 - 800

10k_m = 81.6

k_m = 81.6/10

k_m = 8.16 uM

8 0

3 years ago

Need help please please

trasher [3.6K]

Answer: 50%

Explanation:

8 0

3 years ago