The surface area of triangular prism is 117.12 mm²
<u>Explanation:</u>
Base side, a = 9 mm
Base side, b = 6.6 mm
Base side, c = 5.2 mm
Height, h = 4 mm
Total surface area = ?
We know,
Surface area, A = 2 Ab ( a+b+c) h
Ab = √s(s-a) (s-b) (s-c)
s = a+b+c/2
Solving for A
A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴
A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴
A = 117.12 mm²
Therefore, the surface area of triangular prism is 117.12 mm²
Answer:
See below.
Step-by-step explanation:
1) 4x + 8 = 2x + 10
2x = 2
x = 1
2) 9y - 3 = 6y + 12
3y = 15
y = 5
3) 8m + 4 = 4m - 20
4m = -24
m = -6
4) 11z - 14 = 5z + 4
6z = 18
z = 3
5) 3q - 6 = 8q - 6
5q = 0
q = 0
6) 20n + 7 = 6n - 21
14n = -28
n = -2
7) 2w - 8 = 7w - 3
5w = -5
w = -1
8) 9k + 4 = k - 12
8k = -16
k = -2
Answer:
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Step-by-step explanation:
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Answer:
2x-8d
Step-by-step explanation: