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3 years ago

Middle school math problem.....

Mathematics

1 answer:

Lynna [10]3 years ago

4 0

Answer:

hi bro how are yuo join this meeting i will say you ans

Step-by-step explanation:

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3,480

Serjik [45]

Answer

explanation

3480ones = 3480x1=3480

8 0

2 years ago

A rectangle photograph is mounted on a square piece of cardboard whose sides have length of X. The border of the surroundings th

Tju [1.3M]

The third choice.
The sides of the photo plus the margins of the border equal x.

7 0

3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe

k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and Studied for the Midterm = 75

Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

$N=(25+60)+(40+60) - 60\\N= 125$

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

$P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%$

3 0

3 years ago

Visitors to a cinematic are either children, adults or pensioners. Ratio of children to adult visitors is 1:2 Ratio of adults to

VMariaS [17]

Ratio of children, adults and pensioners is 1 : 2 : 8/3 = 3 : 6 : 8.

Let, 3x is number of children.

So, 6x is number of adults and 8x is number of pensioners.

Now,

3x + 6x + 8x = 85

17x = 85

x = 5

Therefore, number of pensioners are 8×5 = 40.

Hence, this is the required solution.

7 0

3 years ago