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3 years ago

Select the correct answer.

Mathematics

1 answer:

GaryK [48]3 years ago

3 0

Answer:

C. 5 × 3

Step-by-step explanation:

The order of a matrix is the number of rows and columns that a matrix has. Rows are listed first and columns are listed second. The matrix has 5 rows going across horizontally and 3 columns going down vertically.

So, the order of the matrix is 5 × 3.

Hope that helps.

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Find a formula for the inverse of the function. f(x) = e^6x − 9

STatiana [176]

Answer:

$f^{-1}(x)=\frac{1}{6}\ln(x+9)$

Step-by-step explanation:

So we have the function:

$f(x)=e^{6x}-9$

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

$x=e^{6f^{-1}(x)}-9$

Add 9 to both sides:

$x+9=e^{6f^{-1}(x)}$

Take the natural log of both sides:

$\ln(x+9)=\ln(e^{6f^{-1}(x)})$

The right side cancels:

$\ln(x+9)=6f^{-1}(x)$

Divide both sides by 6:

$f^{-1}(x)=\frac{1}{6}\ln(x+9)$

And we're done!

7 0

3 years ago

What number is opposite of 56

OLga [1]

Answer:

- 56

Step-by-step explanation:

The opposite of a number is its negative value

Then the opposite of 56 is - 56

4 0

3 years ago

Read 2 more answers

PLS I GIVE BRAINLIEST

matrenka [14]

The size of the angle QUP in the system formed by the equilateral triangle QUR, the equilateral triangle PUT and the square RUTS is equal to 150°.

<h3>How to determine a missing angle within a geometrical system</h3>

By Euclidean geometry we know that squares are quadrilaterals with four sides of equal length and four right angles and triangles are equilateral when its three sides have equal length and three angles with a measure of 60°. In addition, a complete revolution has a measure of 360°.

Finally, we must solve the following equation for the angle QUP:

m∠QUR + m∠QUP + m∠PUT + m∠RUT = 360

60 + m∠QUP + 60 + 90 = 360

m∠QUP + 210 = 360

m∠QUP = 150

The size of the angle QUP in the system formed by the equilateral triangle QUR, the equilateral triangle PUT and the square RUTS is equal to 150°. $\blacksquare$