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finlep [7]
3 years ago
6

For a standard normal distribution, which of the following expressions must always be equal to 1?

Mathematics
2 answers:
frosja888 [35]3 years ago
8 0
For a standard normal distribution, the expression that is always equal to 1 is P(z≤-a)+P(-a≤z≤a)+P(Z≥a). This expression represents all of the possible values in a curve, or in other words, the total area of a curve. According to standard normal distribution, the total area of a curve is always equal to 1.


Alchen [17]3 years ago
4 0

Answer: D

Step-by-step explanation: Edg.

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(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

4 0
2 years ago
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Answer:

inside

√((5-(-5))^2+((-24)-(-8))^2)=√(10^2+16^2)=√356<25

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