Which of the following sets of numbers could not represent the three sides of a right

1 answer:

Kay [80]3 years ago

4 0

The answer is B). {20,21,28}

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Lelechka [254]

Answer:

danny's offer is cheaper

Step-by-step explanation:

danny = $9 per hour

martin = $16 per hour

6 0

3 years ago

ahrayia [7]

Answer:

75.062c $m^{2}$

Step-by-step explanation:

To find the missing side use pythagorean theorem

So $6^{2} +b^2=8.5^2$

Solve for b, b= 6.021

To find the area use $\frac{1}{2}$ bh

So $\frac{1}{2}$ (6.021+19)(6)= area

And you get 75.062

7 0

3 years ago

Nataliya [291]

four and negative four :)

4 0

3 years ago

Marta_Voda [28]

We can combine x + x and get 2x. So we have:
8x - 2y + 2x. Therefore 10x - 2y is equivalent.

8 0

3 years ago

Alex73 [517]

It is true hopes this helps you

7 0

3 years ago