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Firdavs [7]
1 year ago
13

Write in standard form: x² - 10x + y² - 4y = -28

Mathematics
1 answer:
mel-nik [20]1 year ago
6 0

Answer:

(x - 5) ^2 + (y -2)^2 = 1

Step-by-step explanation:

This is for a circle.

We need to complete the square

(x^2 -10x      ) + ( y^2 -4y       )  = -28

(x^2 - 10x +25) + (y^2 - 4y 2y) = -28 + 25 + 4

(x-5)^2 + (y-2)^2 = 1

The center of this circle would be (5,2)  with a radius of 1.

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Liz flips a coin 40 times. The coin lands heads up 12 times and tails up 28 times. Complete each statement. The theoretical prob
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To factor the quadratic expression x^2−8x−10 by completing the square, what value would be added? A. 64 B. 8 C. 16 D.-16
Elan Coil [88]

Answer:

C

Step-by-step explanation:

When completing the square, we essentially want to create a perfect square trinomial by adding a constant.

If we have the following expression:

x^2+bx

And we want to complete the square, we will need to divide the b-coefficient by half and then square it.

Thus, the added term should be:

(b/2)^2

In the given equation, we have:

(x^2-8x)-10

The b term here is 8. Therefore:

(8/2)^2\\=(4)^2\\=16

The value we would add would be 16.

The answer is C.

Further notes:

To complete the square, add 16 like mentioned earlier. However, we also need to subtract 16 to balance things out:

(x^2-8x)-10\\=(x^2-8x+16)-10-16\\

The expression inside the parentheses is now a perfect square trinomial. Factor it:

=((x)^2-2(4)(x)+(4)^2)-26\\=(x-4)^2-26

And we are done!

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Please help me to find the answer Y=2X 3X+4Y=22 Y=2X 3X+4Y=22 ​
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<h3>System of equations.</h3>

\left\{\begin{array}{ccc}y=2x&(1)\\3x+4y=22&(2)\end{array}\right

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Substitute the value of x to (1):

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Solution:

\huge\boxed{\left\{\begin{array}{ccc}x=2\\y=4\end{array}\right}

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