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Firdavs [7]
2 years ago
13

Write in standard form: x² - 10x + y² - 4y = -28

Mathematics
1 answer:
mel-nik [20]2 years ago
6 0

Answer:

(x - 5) ^2 + (y -2)^2 = 1

Step-by-step explanation:

This is for a circle.

We need to complete the square

(x^2 -10x      ) + ( y^2 -4y       )  = -28

(x^2 - 10x +25) + (y^2 - 4y 2y) = -28 + 25 + 4

(x-5)^2 + (y-2)^2 = 1

The center of this circle would be (5,2)  with a radius of 1.

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Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-
Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

ax^2+bx+c=0

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}

In this case, the exercise gives you this Quadratic equation:

5x^2 + 3x - 4 = 0

You can identify that the numerical coefficients are:

a=5\\\\b=3\\\\c= - 4

Therefore, you can substitute values into the Quadratic formula shown above:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0
3 years ago
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Evaluate -6 minus parentheses -1 parentheses
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-6 minus parentheses -1 parentheses

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6 0
3 years ago
Pls help! I need this for a test tomorrow
sergij07 [2.7K]

Answer:

I didn't know if you wanted to get the answer

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C=2πr solve for r what is the answer for this question and how do you do it
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