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lukranit [14]
3 years ago
15

Evaluate when x = 3 and y = 4. 1/3x -8y

Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0

1/3 times 3 is 1

8 times 4 is 32

soooo.....

1-32 equals negative 31.

hope I helped!!! (:

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Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 6.9 per year. a. Find t
VLD [36.1K]

Answer:

a) 9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b) 4.284 years are expected to have 4 ​hurricanes.

c) The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

6.9 per year.

This means that \mu = 6.9

a. Find the probability​ that, in a​ year, there will be 4 hurricanes.

This is P(X = 4).

So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-6.9}*(6.9)^{4}}{(4)!}

P(X = 4) = 0.0952

9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b. In a 45​-year ​period, how many years are expected to have 4 ​hurricanes?

For each year, the probability is 0.0952.

Multiplying by 45

45*0.0952 = 4.284.

4.284 years are expected to have 4 ​hurricanes.

c. How does the result from part​ (b) compare to a recent period of 45 years in which 4 years had 4 ​hurricanes? Does the Poisson distribution work well​ here?

The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

5 0
3 years ago
John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo
yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6

3 0
2 years ago
Researchers have discovered a new genetic marker for a form of cancer. Twelve percent of the overall population carry this marke
In-s [12.5K]

Answer:

The probability that a person with the marker develops cancer is 0.0725.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = a person has cancer

<em>B</em> = a person carries the marker.

<u>Given:</u>

P (A) = 0.03

P (B) = 0.12

P (B|A) = 0.29

The conditional probability of an event <em>X</em> provided that another event <em>Y</em> has already occurred is:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y)}

Use the conditional probability formula to compute the probability that a person with the marker develops cancer.

P(A|B)=\frac{P(B|A)P(A)}{P(B)} =\frac{0.29\times0.03}{0.12}=0.0725

Thus, the probability that a person with the marker develops cancer is 0.0725.

3 0
3 years ago
Carlos is making belts.He uses 12 rivets each on 4 belts and 15 rivets each on 2 belts.How many rivets are on the belts.
olya-2409 [2.1K]
2x15 + 4x15= your answer good luck !!
7 0
2 years ago
Read 2 more answers
Please answer this in two minutes
morpeh [17]

Answer: g = 5.9

Step-by-step explanation:

SINE RULE

5 / sin(39) = g / sin(48)

so g = 5 / sin(39) * sin(48)

so g  = 5.9 to the nearest tenth.

8 0
3 years ago
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