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Troyanec [42]
3 years ago
14

A recipe uses 3 eggs to make 2 dozen cookies. There are 12 cookies in 1 dozen. How many eggs are used to make 6 dozen cookies? A

.3 B.6 C.9 D.12 please help it would mean a lot <3
Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:

C.9

Step-by-step explanation:

2 doz =3eggs

4 doz = 6 eggs

6 doz = 9 eggs

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Tell whether (5. 10) is a solution of y = 6x – 18
almond37 [142]

Answer:

NO

Step-by-step explanation:

Simply enter 5, 10 in the x and y boxes to get the answer.

10=6(5)-18

10=30-18

10=12

As a consequence, it isn't a feasible option.

8 0
3 years ago
Rewrite the expression in the form 5^n<br><br> (5^-8) (5^-10)
oee [108]

Answer:

Step-by-step explanation:

This problem is all about bases and exponents.  Because we have a quotient and the bases are both 5's, that means that we can use the rule of exponents for quotients to rewrite and simplify:

That's the simplification as long as you are "allowed" to leave the exponent as a negative number.

4 0
3 years ago
Read 2 more answers
What is the slope of the line that contains these points?
miskamm [114]

Answer:

-5/4

Step-by-step explanation:

change in y/change in x

3 0
3 years ago
Read 2 more answers
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
Please solve quickly!!
tamaranim1 [39]

Answer:ya

Step-by-step explanation:

explanation idk

6 0
3 years ago
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