<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
Selecting 5 students to participate in a math contest would require combinations.
<u>SOLUTION:
</u>
given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?
So, we need to differentiate between permutations and combinations.
Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order
Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.
So, now, for our math test, we just require students but not in an order nor with arrangements.
Hence, selecting 5 students to participate in a math contest would require combinations.
Answer:
i think it is b sorry if i'm wrong
Step-by-step explanation:
Answer:
25×4
Step-by-step explanation:
As 24 dollars is one ticket then you do 24×4 which is 96 and 25×4 is 100 which is close to 96.
Hope this helps
THE NUMERATOR IS 11 because a numerator is the number on top
