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lord [1]
3 years ago
5

A pair of pants regularly costs $68. The pants are on sale for 45% of the original price. How much will the discount be?

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

The discounted amount of pair of pants is $37.4

<u>Solution:</u>

Given, A pair of pants regularly costs $68.  

The pants are on sale for 45% of the original price.  

We have to find that how much will the discount be?

Now, <em>discounted amount = original price – sold price </em>

Discounted amount = original price – 45% of original price

Discounted amount = $68 – 45% of $68

\begin{array}{l}{=68-\frac{45}{100} \times 68=68\left(1-\frac{45}{100}\right)=68 \times \frac{100-45}{100}=68 \times \frac{55}{100}} \\\\ {=\frac{3740}{100}=\$ 37.4}\end{array}

Hence, the discounted amount is $37.4

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Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

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and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

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and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

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Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

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Answer:

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For every coin flip, there is a 1/6 chance of getting a three. But since there is another condition, we have to multiply. Multiplying both fractions make 1/12.

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