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atroni [7]
3 years ago
9

Can you please help me with these problems, Thank you

Mathematics
2 answers:
Kaylis [27]3 years ago
7 0
A) A mark dwon greater than 99% and less than 100%

Mark down 99.1% of x

Original price: x

Final price: original price -  mark down = x - 0.991 x = 0.009x

=> If orginal price is 1000 and mark down is 99.1% , final price = 0.009*1000 = 9

You can check that the mark down is 99.1% of 1000 = 991.

b) A mark down that is less than 1%

Mark down: 0.1%

Original price: 10,000

Mark down: 10,000 * 0.1% = 10

Final price: 10,000 - 10 = 9,990

c) A mark up that is more than 200%

Mark up: 300%

Original price: 100

=> final price = 100 + 100*300% = 100 + 300 = 400

 

VashaNatasha [74]3 years ago
3 0
Cost of tiles=288*80=$230.40
you paid 200 bucks
.You will get nothing back but you have to pay more 30.40 bucks
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(x+5)(x+7)

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4 years ago
Factor the trinomial x^2 - 8x + 16
Eva8 [605]
Hey there mate!

Your answer: \boxed{(x-4)^2}

Factoring : x^2-8x+16  \\ \\ \\  \left[\begin{array}{ccc}  -16    +    -1    =    -17 
\\ \\  -8    +    -2    =    -10  \\ \\ -4    +    -4    =    -8\end{array}\right] (That's \ it!) 
\\ \\ \\ Add \ up \ the  \first \ 2 \ terms, \ pulling \ out \ like \ factors : \\  \\ x * (x-4) \\ \\
              Add \ up \ the \ last \ 2 \ terms, \ pulling \ out \ common \ factors : \\ \\
                    4 * (x-4) \\ \\  Multiply  \\ \\ \boxed{(x-4)  by  (x-4) } \\ \\ \\

Your \ correct \ correct \ answer \ would \ be... \\ 

\boxed{\boxed{(x-4)^2}}

I hope this helps you!
5 0
3 years ago
What fraction has a numerator of 44
Paha777 [63]
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Which of the following represents the opposite of - 547
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7 0
3 years ago
Can someone answer this question please?
Troyanec [42]

The solution to the inequality 3x-3\leq -15\,\,or\,\,4x-1\geq 11 is x\leq -3\,\,or\,\,x\geq 4

The number line is shown in figure attached.

Step-by-step explanation:

We need to solve the inequality: 3x-3\leq -15\,\,or\,\,4x-1\geq 11

Solving the inequality:

3x-3\leq -15\,\,or\,\,4x-1\geq 11\\Adding\,\,3\,\,on\,\,both\,\,sides\,\,and\,\,1\,\,on\,\,both\,\,sides\\3x-3+3\leq -15+3\,\,or\,\,4x-1+1\geq 11+1\\3x\leq -12\,\,or\,\,4x\geq 12

Divide by 3 and divide by 12

x\leq \frac{-12}{3} \,\,or\,\,x\geq \frac{12}{4} \\x\leq -4\,\,or\,\,x\geq 3

So, value of x can be less than equal to -4 or value of x is greater than equal to 3.

The number line is shown in figure attached.

The solution to the inequality 3x-3\leq -15\,\,or\,\,4x-1\geq 11 is x\leq -3\,\,or\,\,x\geq 4

Keywords: Solving inequalities

Learn more about Solving inequalities at:

  • brainly.com/question/1465430
  • brainly.com/question/6703816
  • brainly.com/question/4192226

#learnwithBrainly

7 0
3 years ago
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