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alekssr [168]
3 years ago
10

Suppose interstate highways join the six towns A, B, C, D,E,F as follows: 1-77 goes from B through A to 1-82 goes from C through

D then through B to F: 1-85 goes from D through A to F; 1-90 goes from C through E to F and 1-91 goes from D to E.
a) Draw a graph of the network with vertices for towns and edges for segments of interstates linking neighboring towns. b) What is the minimum number of edges whose removal prevents travel between some pair of towns?
c) Is it possible to take a trip starting from town C that goes to every town without using any interstate highway for more than one edge (the trip need not return to C?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0

Answer:

b)2

c) C to D to E to F to A to B

Step-by-step explanation:

The complete answer is found in the attachment.

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Please Help ASAP also SHOW work please!!!!! Thank you. please give correct answer
Kryger [21]

62 can go into 584 nine times which will be 558. 584-558=26. Bring down your 1 which will now be 261. 62 can go into 261 four times which will be 248. 261-242=13. So the top answer should be, 94 R 13.

5 0
2 years ago
Helpp, since this question is a bit hard, ill give brainliest and 20 pts.
Morgarella [4.7K]

Step-by-step explanation:

A. When dealing with large numbers, sometimes it's easier to write them in a form of exponents of number ten. The value of the exponent shows how many times we multiply 10 by itself. That means that 10^3 is 10•10•10 or that 10^6 is 10•10•10•10•10•10.

So, when finding how many times on number is greater then the other, we need to divide them. We divide 8x10^6 by 2x10^5. It is done by dividing the numbers and subtracting the exponents; 8/2=4 and 10^6/10^5 is 10^6-5=10^1. So the correct answer is 4x10^1 which is 4x10, and that is 40.

B. Now, we have a total number of coins (2.25x10^5), and diametar of a coin (19mm = 19x10^-6km). Our task is to calculate the distance across which the coiks laid side-by-side would expand. We can find this by multiplying the number of coins with a diametar of single penny, 2.25x10^5•19x10^-6. Multiplying is done by multiplying the numbers (2.25x19=42.75) and adding the exponents (5+(-6)=5-6=-1). So, the distance is 42.75x10^-1km, which equals to 4.275 km. Obviously, this is less then the stated 5 km given in the text, so the reportet's statement is false.

5 0
3 years ago
What is the value of 2 over 3 to the power of 0 to the power of -3
Schach [20]

Answer:

((\frac{2}{3})^0)^{-3}=1

Step-by-step explanation:

We need to find the value of ((\frac{2}{3})^0)^{-3}

Solving:

We know, (a^b)^n = a^{b*n}

((\frac{2}{3})^{0*-3})

(\frac{2}{3})^0

a^0 = 1

so,

(\frac{2}{3})^0=1

So, the value of ((\frac{2}{3})^0)^{-3}=1

5 0
3 years ago
The 2 in 21 represents how many times the value of the 2 in 82?
anyanavicka [17]

Answer:

10 times as much

Step-by-step explanation:

the 2 in 82 is worth 2 ones while the 2 in 21 is worth 10 ones

4 0
2 years ago
Read 2 more answers
What is the answer to the equation -0.5x+1.75x<-1.75+2.75x
PIT_PIT [208]
X>7/6
Combine like terms
Subtract 2.75x from both sides
Combine like terms
Divide -1.5 from both sides

8 0
3 years ago
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