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emmasim [6.3K]
3 years ago
7

7.7 times 10 to the 12th power

Mathematics
2 answers:
ANEK [815]3 years ago
6 0

Answer:

7.7e+12

Step-by-step explanation:

<em>because.....</em>

<em>=(7.7)(1000000000000)</em>

<em>=7700000000000</em>

<em>Therefor, the correct answer would be 7.7e+12</em>

<em>* Hopefully this helps:) Mark me the brainliest:)!!!</em>

<em></em>

podryga [215]3 years ago
4 0

That is 77 to the power of twelve which is 77x77x77x77x77x77x77x77x77x77x77x77.

Answer:43439888521963583647921

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E. Polynomials
horsena [70]

Answer:

see below

Step-by-step explanation:

1. 7x+2x+19x

(7, 2, 19) x

=28x

2. -6x-3+3x-9

-3x-3-9

=3x-12

3. (3x-4y) -(x+2y)

3x-4y-x-2y

=2x-6y

4. 18x5 - 6x3

90-18

=72

5. (x+5)(x-7)

x²-7x+5x-35

=x²-2x-35

6 0
3 years ago
Why is 1.4 a rational number? Please help with a explanation!
Nonamiya [84]

Answer:

1.4 is a rational number because it has a terminal decimals. it is the same as 14/10

8 0
3 years ago
Read 2 more answers
If we add, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and –3xz + 5x – 2xy, then the answer is:
denis-greek [22]

Answer:

A. 5xy + 9yz +3zx + 5x – 4y

Step-by-step explanation:

Because it is the "<u>Correct Answer</u>"

8 0
3 years ago
Help please, will mark brainliest ​
mario62 [17]

Answer:

Step-by-step explanation:

LET ORANGES=X

PEARS ARE 3 TIMES =3X

LET CHILDREN=Y

IF WE GIVE 5 ORANGES PER CHILD WE NEED 5Y ORANGES.SO THIS =X

X=5Y........................I

IF WE GIVE 8 PEARS PER CHILD WE NEED 8Y PERARS...THERE ARE STILL 21 PEARS LEFT OUT AFTER THIS THAT IS

8Y+21=3X....................II

SUBSTITUTING FOR X FROM EQN.I..

8Y+21=3*5Y

15Y-8Y=21

7Y=21

Y=3

X==5Y=5*3=15..

SO CHILDREN =3

ORANGES=15

PEARS=3*15=45

THANKYOU AND PLEASE AMRK IT BRAINLIEST

8 0
3 years ago
Write an equation for a rational function with: vertical asymptotes at x = 2 and x = -5 x-intercepts (-1,0) and (1,0) horizontal
solong [7]

Given vertical asymptotes x = 2 and x = -5 .

Therefore Factors of denominator (x-2)(x+5).

x-intercepts (-1,0) and (1,0) .

Therefore factors of (x+1)(x-1).

So far we got rational function = \frac{(x+1)(x-1)}{(x-2)(x+5)}.

Now, we are given horizontal asymptote at y = 9.

Multiplying above express by 9 on the top, we get

f(x)=\frac{9(x+1)(x-1)}{(x-2)(x+5)}.

<h3>Therefore, required rational function is f(x)=\frac{9(x+1)(x-1)}{(x-2)(x+5)}.</h3>
7 0
3 years ago
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