Answer: A = $1503.6
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1000
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
t = 7 years
Therefore,.
A = 1000(1 + 0.06/1)^1 × 7
A = 1000(1.06)^7
A = $1503.6
Multiply straight across and then just simply your answer. I divided by 2.
Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x