Answer:
The volume of the cylinder is decreasing at a rate of 83629.2 m³/h.
Step-by-step explanation:
The volume of a is given by:

Where:
r: is the radius = 55 m
h: is the height = 88 m
We can express the rate of change of the volume of the cylinder as follows:
![\frac{dV}{dt} = \pi[h\frac{2rdr}{dt} + r^{2}\frac{dh}{dt}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cpi%5Bh%5Cfrac%7B2rdr%7D%7Bdt%7D%20%2B%20r%5E%7B2%7D%5Cfrac%7Bdh%7D%7Bdt%7D%5D%20)
If dr/dt = 11 m/h and dh/dt = -44m/h, we have:
![\frac{dV}{dt} = \pi[88 m*2*55 m*11 m/h + (55 m)^{2}*(-44 m/h)] = -83629.2 m^{3}/h](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cpi%5B88%20m%2A2%2A55%20m%2A11%20m%2Fh%20%2B%20%2855%20m%29%5E%7B2%7D%2A%28-44%20m%2Fh%29%5D%20%3D%20-83629.2%20m%5E%7B3%7D%2Fh%20)
Therefore, the volume of the cylinder is decreasing at a rate of 83629.2 m³/h.
I hope it helps you!
Answer:
2/14
Step-by-step explanation:
I think you double both, but I'm, not sure :)
Answer:
why would you put college and its g(t)= -16^2 +80t + 0
Step-by-step explanation:
this is because it is