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3 years ago

Need help with this circumference question

Mathematics

2 answers:

shutvik [7]3 years ago

8 0

Hold on I have that answer

Alexxandr [17]3 years ago

5 0

Answer:

The numerical value of circumference is greater than the numerical value of area

Step-by-step explanation:

Given

circumference= 2π

formula for circumference of circle is 2πr

hence r of given circle is 1

formula for area of circle is πr^2

putting r=1 in above equation

Area of given circle= π(1)^2

= π

As 2π>π

The numerical value of circumference is greater than the numerical value of area!

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Use the arc length formula and the given information to find θ. s = 4 m, r = 13 m; θ = ?

solong [7]

C=2πr and the circumference is measured at 360°

So if we were to set up a proportion we could say:

s/(2πr)=α/360

α=180s/(πr)

We are given that s=4m and r=13m so:

α=180(4)/(13π)

α=720/(13π) m which is approximately:

α≈17.63°

Which is why radians are often used, because in radians...

α=[720/(13π)](π/180)

α=4/13 rads

Or the arc length in radians is simply expressed as:

s=rα

α=s/r (which is much neater :P) then it is plain to see that:

α=4/13 rads

7 0

3 years ago

Read 2 more answers

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Diano4ka-milaya [45]

It will be 3 hours until they are the same hight

7 0

3 years ago

Expand and simplify (2x−12) ^2

lubasha [3.4K]

Answer:

$\boxed{4x^{2} - 48x + 144}$

Step-by-step explanation:

Given expression:

(2x - 12)²

To simplify the expression, we will use the formula (a - b)² = a² - 2ab + b².

[Where "a and b" are the first and second term in (a - b)²]

$\rightarrowtail (2x - 12)^{2}$

In this case, the first term of (2x - 12)² is "2x" and the second term is "12".

$\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\small\text{First term = a = 2x; Second term = b = 12]}$

Now, simplify the expression.

$\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2}$

$\rightarrowtail (2x)(2x) - (4x)(12) + (12)(12)$

$\rightarrowtail \boxed{4x^{2} - 48x + 144}$

4 0

2 years ago

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

2 years ago

I've been trying to get an answer for this all day and don't know where to begin what is the answer like I have no clue

Shtirlitz [24]

so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.

we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.

$\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78$

6 0

3 years ago