Answer:
Answer 14
Step-by-step explanation:
answer 37.38
Answer:
Step-by-step explanation:
P = {x : x is a real number between 2 and 7}
{x: 3,4,5,6}
Q = {x : x is all rational number between 2 and 7}
{4 }
We know that P contains all the rational numbers between 2 and 7.
And P ∪ Q and Q ∪ P each of them contain all the real numbers which are between 2 and 7.
{3,4,5,6}
Here Q is the proper subset of P
P ∩ Q = Q ∩ P = Q= {4}
6+5=11
or
6+5=?
It shows we originally have 6 and now have 5 more having a total of 11
