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astraxan [27]
3 years ago
8

The first three steps of completing the square to solve a quadratic equation x^2+ 8x+0=0are shown below What are the next three

steps
Mathematics
1 answer:
Setler [38]3 years ago
8 0

Step-by-step explanation:

x^2 + 8x + 0 = 0

Completing the square just means getting yourself a perfect square trinomial on the left side of your equation. It makes factoring easier for you. The steps are like this:

x² + 8x + 0 = 0 ... take the middle coefficient, 8, divide it by 2, and square it. Same process every time. Divide middle by two, square it. This gives you the "perfect square" of your equation. In this case, 8/2 = 4, and 4² = 16. So what you do is add 16 to BOTH sides of the equation.

x² + 8x + 16 = 16 ... factor the left side

(x + 4)(x + 4) = 16 ... notice that your two factors on the left are identical

(x + 4)² = 16 ... now we want to solve for x. Start by taking the square root of both sides

x + 4 = √16 ... √16 can give us two results: -4 and 4. So solve for both.

x + 4 = 4         x + 4 = -4  ... solve for x

x = 0,              x = -8

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Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it
Novay_Z [31]

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

so

z^{2}=\frac{Ak}{Aj}

we have

z=4

substitute

4^{2}=\frac{Ak}{Aj}

16=\frac{Ak}{Aj}

Ak=16Aj

therefore

The area of triangle K is 16 times greater than the area of triangle J

4 0
3 years ago
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One leg of a right triangle is 4 cm the hypotenuse is 10 cm how long it the other leg
ASHA 777 [7]
I hope this will work.
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3 years ago
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Dan's school is selling tickets to a play. On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets
VashaNatasha [74]

Answer:

Let's define the variables:

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S = price of one student ticket.

We know that:

"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."

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Then we have a system of equations:

A + 6*S = $69

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To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:

A = $69 - 6*S

Now let's replace this in the other equation:

7*($69 - 6*S) + 7*S = $150

Now we can solve this for S.

$483 - 42*S + 7*S = $150

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$483 - $150 = 35*S

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$333/35 = S

$9.51 = S

That we could round to $9.50

That is the price of one student ticket.

4 0
3 years ago
Linda and Colleen both leave the library at the same time, but in opposite direction. If Colleen travels 8mph faster than Linda
pshichka [43]
X - Linda's speed
(x+8 )- Colleen's speed

8x - Linda's distance for 8 h
8(x+8) = 8x+64  - Colleen's distance for 8 h

8x + 8x + 64 = 176 - distance between Colleen and Linda after 8 h


8x + 8x + 64 = 176 
16x +64 = 176
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x+8
= 7+8 = 15 mph Colleen's speed
8 0
3 years ago
They're the same because...?
emmasim [6.3K]

Answer:

thay still give you the same answer

Step-by-step explanation:

2x3x4=24

while bxh

6x4 =24

do good

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