You should have a theorem that says that a midsegment between two sides is parallel to and half the length of the third side.
<span>Since DF is a midsegment = 17, then AC will be 17*2 = 34 </span>
<span>The fact that EC = 30 is extra information, given to throw you off (it worked on me for a bit)</span>
Answer:
Step-by-step explanation:
I am in ninth grade and taking Algebra, I can maybe help you, what is it you need help with/are confused about?
If sin < 0 and sec > 0, theta must be located in quadrant IV where tan < 0
Use x for theta
So to compute for this:Sec x = √10/3
cos x = 3 / √10
sin x = -√(1-cos^2x)
= -√ (1-(9/10))
= -√ (1/10)
= -1/√10
tan x = sin x/cos x
=-1/3 is the answer for this problem.
Answer:
45x^8 y^5
Step-by-step explanation: