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4 years ago

The width of a rectangle is 6 units less than the length. The area of the rectangle is 7

Mathematics

1 answer:

Reil [10]4 years ago

4 0

Answer:

1 1/6 units

Step-by-step explanation:

area = length * width

6 * 1 1/6 = 7

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a large data sample of heights of US women is normally distributed with a mean height of 64.2 inches and a standard deviation of

Romashka-Z-Leto [24]

Answer:

I have the same question and i am very confused.

Step-by-step explanation:

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4 years ago

Which graph represents the function there are 2 more graphs but it won't add it

Anon25 [30]

Answer:

$f(x) = 9x^2+9x - 18/3x + 6\\= 9(x^2 + x - 2)/3(x+2)\\= 3(x^2+x-2)/x+2\\= 3(x+2)(x-1)/x+2\\= 3x - 3$

so y = 3x - 3

since 3x + 6 is on the bottom,

$3x + 6\neq 0\\3x\neq -6\\x\neq -2$

so this means it should be the graph of y = 3x - 3, but with a hole at (-2, -9)

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2 years ago

Help me with this one please

Drupady [299]

Step-by-step explanation:

1cm = 16 km

Distance between York and London = 23.1 cm

Now the real distance between York and London = 23.1 * 16

= 369.6 km

6 0

4 years ago

Logan ate 1.438 pounds of grapes. Ralph ate 1.44 pounds of grapes. Which brother ate more grapes?

Ray Of Light [21]

You do 1.44 - 1.438 which the difference is .002

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3 years ago

Read 2 more answers

An automobile manufacturer has given its jeep a 51.3 miles/gallon (MPG) rating. An independent testing firm has been contracted

Nitella [24]

Answer:

The p-value of the test is 0.2262 > 0.02, which means that the decision is to fail to reject the null hypothesis.

Step-by-step explanation:

An automobile manufacturer has given its jeep a 51.3 miles/gallon (MPG) rating.

At the null hypothesis, we test if the mean is of 51.3, that is:

$H_0: \mu = 51.3$

An independent testing firm has been contracted to test the actual MPG for this jeep since it is believed that the jeep has an incorrect manufacturer's MPG rating.

This means that at the alternative hypothesis, we test if the mean is different of 51.3, that is:

$H_0: \mu \neq 51.3$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

51.3 is tested at the null hypothesis:

This means that $\mu = 51.3$

After testing 230 jeeps, they found a mean MPG of 51.1. Assume the population variance is known to be 6.25.

This means that $n = 230, X = 51.1, \sigma = \sqrt{6.25} = 2.5$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{51.1 - 51.3}{\frac{2.5}{\sqrt{230}}}$

$z = -1.21$

P-value of the test and decision:

The p-value of the test is the probability of the sample mean differing from 51.1 by at least 0.2, which is P(|z| > 1.21), which is 2 multiplied by the p-value of z = -1.21.

Looking at the z-table, z = -1.21 has a p-value of 0.1131.

2*0.1131 = 0.2262

The p-value of the test is 0.2262 > 0.02, which means that the decision is to fail to reject the null hypothesis.

8 0

3 years ago