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Ber [7]
3 years ago
14

PLS!!! HELP ME!!!! I WILL MARK U!!

Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

-47.4

Step-by-step explanation:

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1 times 10 to the 21st power
balandron [24]

Answer:

I believe the answer to this question is: 1 x 10^21 equal to 1000000000000000000000.

7 0
3 years ago
15 POINTS! someone pls answer
photoshop1234 [79]

Answer:

2(\frac{1}{2} *20*50)+2(\frac{1}{2} *20*10)

Step-by-step explanation:

The formula for the area of a triangle is \frac{1}{2} *b*h

The triangles that can be made is the triangle that has legs 20 and 50 and the triangle that has legs 20 and 10.

Since there are 2 of each triangles, we get:

2(\frac{1}{2} *20*50)+2(\frac{1}{2} *20*10)

The answer that fits is the first option.

5 0
3 years ago
2.7 times a number equals 8.37?
KIM [24]

Answer:

22.599

PLEASE SAID THANKS

4 0
2 years ago
Read 2 more answers
Which expression is equivalent to Assume x > 0 and y 0.
Svetach [21]

we have

\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}}

we know that

\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}} =\sqrt{\frac{55}{11}\frac{x^{7}}{x^{11}}\frac{y^{6}}{y^{8}}} \\ \\= \sqrt{\frac{5}{x^{4} y^{2}}} \\ \\ =\frac{\sqrt{5}}{x^{2} y}

therefore

<u>the answer is</u>

The expression equivalent is  \frac{\sqrt{5}}{x^{2} y}

3 0
3 years ago
Read 2 more answers
Question is in image <br> In the diagram below, ST is parallel to PR
likoan [24]

Answer:

  D.

Step-by-step explanation:

There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.

Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...

  SQ/PQ = TQ/RQ

From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.

  (PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem

  1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division

  -PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)

  PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)

5 0
2 years ago
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