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posledela
3 years ago
10

Solve the proportion 8/3= x/14

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

\frac{3}{112}
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Please answer this math question, thank you!
scZoUnD [109]
The answer is A because it is quartile 1 of 4. There are 4 quartiles so logially 1 out of 4 is 25%. Hope this helps!
7 0
4 years ago
Absolute value of -1 +3i
katrin2010 [14]

Answer:

1+3i

Step-by-step explanation:

i is a variable. -1 has an absolute value of 1. 3i is multiplying i by 3.

4 0
3 years ago
How do I Express the inequality x < 7 using interval notation.
Sedaia [141]

Answer:  (-\infty, 7)

You can write this as (-infinity, 7) if you aren't able to use the infinity symbol.

====================================================

Explanation:

Think of x < 7 as writing -\infty < x < 7

So x is between negative infinity and 7, excluding both endpoints.

To write -\infty < x < 7 in interval notation, we write (-\infty, 7)

The curved parenthesis tell us to exclude the endpoint.

7 0
3 years ago
If f(x) = 3х + 10, find f(4)<br> A<br> f(4) = 17<br> f(4) = 22<br> с<br> 22<br> f(4) = 17
slava [35]
The second one is the answer: f(4) = 22
5 0
3 years ago
Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
Read 2 more answers
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