Answer:
mean that your number cold promble be thorugh 12-100 to equal defined the varible to number is an futions of intrution grade promage
The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11
<h3>How to solve the function values?</h3>
As a general rule, we have:
f⁻¹(f(x)) = x
Substitute 58 for x
So, we have:
f⁻¹(f(58)) = 58
Hence, the value of f⁻¹(f(58)) is 58
Also, we have:
f(f(5))
From the table, we have:
f(5) = 9
So, we have:
f(f(5)) = f(9)
From the table, we have:
f(9) = 11
So, we have:
f(f(5)) = 11
Hence, the value of the function f(f(5)) is 11
Read more about invertible function at:
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1) b. 8
2) b. 15
Do you need an explanation?
Answer:
Soln:
Step-by-step explanation:
Here,
Base(b) =9
Opposite/Perpendicular (p)= x
Hypotenus (h) = 24
We know,
(p)^2 = (h)^2 - (b)^2
(x)^2 = (24)^2 - (9)^2
x^2 = 576 - 81
x^2 = 495
x = root under 495
Answer:
C
Step-by-step explanation:
Using the coefficients of each term and evaluating for h = - 4
- 4 | 1 - 7 - 7 20
↓ - 4 44 - 148
---------------------------
1 - 11 37 - 128 ← remainder
Quotient = x² - 11x + 37 , R - 128
