yes, it does not matter if the y is at the beginning or at the end. However, most teachers usually prefer to have the y at the beginning as it is easier to read.

6 0

3 years ago

(3ab-2a-2)-(4ab-4) find the difference

m_a_m_a [10]

(3ab-2a-2)-(4ab-4)=
3ab-2a-2-4ab+4=-ab-2a+2

4 0

4 years ago

Given square ABCD, with point P on side AB , point Q on side BC, point R on side CD, and point S on side DA as shown. Additional

sveta [45]

The ratio of the area of square PQRS to the area of square ABCD is 5/9

<h3>Area of square ABCD</h3>

Assume the measure of the side lengths of the square ABCD is 1, then the area of the square ABCD is:

$A_1 = 1 \times 1$

$A_1 = 1$

See attachment for the diagram that represents the relationship between both squares.

<h3 /><h3>Pythagoras theorem</h3>

The measure of length PQ is then calculated using the following Pythagoras theorem:

$PQ^2 = (\frac 13)^2 + (\frac 23)^2$

Evaluate the squares

$PQ^2 =\frac 19 + \frac 49$

Add the fractions

$PQ^2 =\frac 59$

<h3>Area of square PQRS</h3>

The above represents the area of the square PQRS.

i.e.

$A_2 =\frac 59$

So, the ratio of the area of PQRS to ABCD is:

$Ratio = \frac{A_2}{A_1}$

This gives

$Ratio = \frac{5/9}{1}$

$Ratio = \frac{5}{9}$

Hence, the ratio of the area of square PQRS to the area of square ABCD is 5/9