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irina [24]
3 years ago
8

8.3 Complete the repayment schedule for a $1,300 Loan at 7.5% for 6 months

Mathematics
1 answer:
kotykmax [81]3 years ago
5 0
$2.77 dollars would be the answer I think
You might be interested in
Why resultant magnitude by using Pythagorean theorem is different than using ( x,y )components addition vectors ???
Andreyy89

9514 1404 393

Explanation:

Your different answers came about as a result of an error you made in the Pythagorean theorem calculation.

  √(100 +100) = √200 = 14.142 . . . . same as vector calculation

4 0
3 years ago
For safety reasons, 4 different alarm systems were installed in the vault containing the safety deposit boxes at a Beverly Hills
Evgen [1.6K]

Answer:

<em>99.93%</em>

Step-by-step explanation:

<u>Probability of Independent Events</u>

Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.

We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.

We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.

The probability that none of the systems detect the theft is

P(0)=q^4=0.16^4=0.00065536

Thus, the probability that at least one of the systems detect the theft is

P(x\geq1)=1-P(0)=1-0.00065536=0.9993

That means a 99.93%

3 0
3 years ago
Middle School: Math (10 Points)
sasho [114]
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:

A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?

You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked

2) a - 2%  as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.  

b - 1,000,000/2500 = 400
400 packages are defective each year
5 0
4 years ago
Q= QUADRADO
Lubov Fominskaja [6]
Answer
C x Q x T = ? = 24
6 0
3 years ago
Explain what is wrong with the figure below.
Georgia [21]

Answer:

The diagonal side length shouldn't be 14. Or one of the side lengths shouldn't be what it is.

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
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