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Strike441 [17]
3 years ago
7

For safety reasons, 4 different alarm systems were installed in the vault containing the safety deposit boxes at a Beverly Hills

bank. Each of the 4 systems detects theft with a probability of 0.84 independently of the others. The bank, obviously, is interested in the probability that when a theft occurs,at least one of the 4 systems will detect it. What is the probability that when a theft occurs, at least oneof the 4 systems will detect it?
Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer:

<em>99.93%</em>

Step-by-step explanation:

<u>Probability of Independent Events</u>

Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.

We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.

We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.

The probability that none of the systems detect the theft is

P(0)=q^4=0.16^4=0.00065536

Thus, the probability that at least one of the systems detect the theft is

P(x\geq1)=1-P(0)=1-0.00065536=0.9993

That means a 99.93%

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Reflection about y=2

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Triangle A should be reflected about y=2 to map it onto Triangle B.

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false

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Eva collected 2,090 coins. Elijah collected 1,910 coins. They divided all their coins into 8 equal stacks. How many coins are in
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3 years ago
Elizabeth has $10, $5, and $1 bills worth $101. she has five more five dollar bills than ten dollar bills and 4 times more 1 dol
vesna_86 [32]

Let x be number of $10 dollar bills

Let y be number of $5 dollar bills

Let z be number of $1 dollar bills

From the question, we can come up with three equations (so we can find the values of x, y & z) :

  • 10x + 5y + z = 101
  • y - x = 5
  • z = 4x

The first equation comes from finding the total money Elizabeth has, which is $101.

The second equation comes from value of y (number of $5 bills) is more than value of x (number of $10 bills) by 5 dollars.

The third equation comes from the value of z (number of $1 bills) being 4 times more than the value of x (number of $10 bills).

Now, we will begin to find the value of x, y & z.

From the first equation,

10x + 5y + z = 101

Substitute the third equation (z = 4x) into z:

10x + 5y + 4x = 101

Simplify this and you get,

14x + 5y = 101

Now, we use the second equation. The second equation is y - x = 5. If we try to make y as the subject, it becomes y = 5 + x.

Now, substitute this into the value of y of the last working we did:

14x + 5(5+x) = 101

Simplify that and it becomes:

x = 4

Then, substitute this value of x into the second and third equations to find y and z.

y - x = 5

y - 4 = 5

y = 9

z = 4x

z = 4(4)

z = 16

Finally, let's check these answers by substituting them into the first equation to try and see if the total value is <em>really</em> $101.

10x + 5y + z = 10(4) + 5(9) + 16

10x + 5y + z = 40 + 45 + 16

10x + 5y + z = 101

Thus, our answers are correct. Elizabeth has FOUR $10 bills, NINE $5 bills and SIXTEEN $1 bills.

6 0
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omeli [17]

let nwmber to be X

the number is 12 less than it's square,

so X=12-X^2

=> X^2+X-12=0

=> (X+4)(X-3)=0

=>X= 3, or X=-4

in math we don't usually take negative numbers into account so your number would be 3

5 0
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